What is the perimeter of the following polygon? 50 units 48 units 47 units 46 units

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What is the perimeter of the following polygon? 50 units 48 units 47 units 46 units

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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have you tried adding all the sides? perimeter means sum of all sides..
|dw:1339668880511:dw| if 16 is the base that means the two smaller lines are 8 each

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|dw:1339668933137:dw|
now use pythagorean theorem to find x \[x = \sqrt{15^2 + 8^2}\] \[x = \sqrt{225 + 64}\] do you have a calculator? i dont
no i dont im sorry
x = 17..
it seems \[x = \sqrt{289}\] \[x = 17\] i remembered lol
Perimeter is : 50
|dw:1339669078571:dw| now add 17 + 17 + 16
are you sure about that @waterineyes ? why don't you back your answers up /:)
do you get the solution @imilee ?
No, i have no clue how to
how to what? how to add 17 + 17 + 16?
Sorry, lgbasallote what do you mean by why you back your answers up??
i meant don't just give answers...back them up with solutions ;)
You are giving the solutions, so I thought I can give answers so that it becomes easy for the person who has asked the question..
SO the answer is 50...... ok all you guys had to say is what i needed to doooo..... 17+17+16. Thank for helping you two :)
for future note i think it's best if the askers get the answers by themselves ;) answers usually distract them from the solution
@imilee how 17 was got is pretty important too ;)
ok i will take care of it...

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