A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Tutor question #1
Simplify the following:
\[\frac{1}{\sqrt2 + \sqrt3 + \sqrt5}\]
(conditions: pen, paper, no calculator, done in 2 minutes)
*
 2 years ago
Tutor question #1 Simplify the following: \[\frac{1}{\sqrt2 + \sqrt3 + \sqrt5}\] (conditions: pen, paper, no calculator, done in 2 minutes) *

This Question is Closed

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5I got \[ \frac{2\sqrt3 + 3\sqrt2  \sqrt{30}}{12}\] Was that right?

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0HUNDRED PERCENT!!!!!!!!!!!!!

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5But it looks so messy...

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0i got something different: isn't it you cant have radicals under a fraction so you multiply by the conjugate?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5That's what rationalise means

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0Not messy at all, this is the only way to go about it.

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0yes but if you multiply 1 by the conjugate pair you get the conjugate pair.. your numerator seems wrong..

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0otherwise can someone please show me a step by step to how you got that answer? and i'll show you what i did :)

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5luckily, I haven't deleted that.. \[(\sqrt2 + \sqrt3 + \sqrt5)(\sqrt2 + \sqrt3  \sqrt5)\]\[ = (\sqrt2 + \sqrt3)^25\]\[ = 2 + 3 + 2\sqrt65\]\[=2\sqrt6\] \[\frac{1}{\sqrt2 + \sqrt3 + \sqrt5}\]\[ = \frac{\sqrt2 + \sqrt3  \sqrt5}{(\sqrt2 + \sqrt3 + \sqrt5)(\sqrt2 + \sqrt3  \sqrt5)}\]\[ = \frac{\sqrt2 + \sqrt3  \sqrt5}{2\sqrt6}\]\[ = \frac{2\sqrt3 + 3\sqrt2  \sqrt{30}}{12}\]

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0\[1/(\sqrt{2}+\sqrt{3}+\sqrt{5})=1/(a+\sqrt{5})=(asqrt{5})/(a^{2}5)\] \[(\sqrt{2}+\sqrt{3}\sqrt{5})/(55+\sqrt{6})\] \[\sqrt{2}+\sqrt{3}\sqrt{5}/2\sqrt{6}=2.\sqrt{3}+2.\sqrt{2}\sqrt{30}/12\]

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0I ended at the second to last step... where did you get the 2 in front of the radicals if you are multiplying by 1?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5see the first part of it..

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.055+2sqrt(6)*

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5@RaphaelFilgueiras The second term of the numerator is 3\sqrt{2} ?! \sqrt{18} = \sqrt{9 times 2} = 3\sqrt2 ...

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0okay, so the you rationalized the second to last line because of the radical at the bottom?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5Of course! That's 'rationalise'

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.0okay sorry, then you are right.. I just wanted to know where I went wrong...

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0no in my solution i put (55+sqrt(5))(WRONG) instead(55+2sqrt(5))

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5Sorry, but I don't know what you're doing.. No offense.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5Do you mind retype it again?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0i did same as you,but call(a=sqrt(2)+sqrt(3))

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5Okay, and the answer is the same?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.5Okay, thanks everyone!!!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.