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May be we can take x^2 as "t" & then factor

I mean\[(t^2-7t+1+5)-5\]

If my brain still works,
Then it becomes
(t-6)(t-1)-5
and then ..?

I should learn this :/

ya it is not going to be factor like this:/
May be @satellite can help us:)

It's @satellite73

And he's offline

oops sorry lol

so we made only this much\[(x^2-6)(x^2-1)-5.\]
now what should we do of {-5}?

I don't think we should do it in this way...

ya u r right @Callisto
But I m thinking more on this.

you need to use synthetic division

@bronzegoddess Can you further explain it?

x^2-6 @ParthKohli

@ParthKohli It's not like that.... and you made mistakes there too...

I deleted it before you noticed :P

lol

I noticed before you deleted :P

ya i too

This degree 4 is eating my head >.<

I m feeling giddy too

@maheshmeghwal9 can you call Yogesh please?

but he is sitting aside of me

we 3 are all here:)

Haha nice

But my wolfy says (x^2 - 3x + 1)(x^2 + 3x + 1)

@bronzegoddess According to the word 'factor', I don't expect there is a remainder.

ya @Callisto is right: D

Hmm but I was telling bronzegoddess that this can be factored. I wanna understand too

LANA THE PROFESSOR :D

Not using synthetic division like that - yes :)
Lana~~~~~~~~~~~~

We must want an exact & good method.

okay, let me do the whole thing again.

very good @ajprincess

but how did she know about adding -3x^3 & something other.
I want to hear from her.

ya but if we didn't know the answer, then what to do
It is the exact problem:/

ya will show that in a few minutes time.

hmm..

Do you know when to use that method?

we use trial and error method when we need to factorise expressions with greater power

when looking for factors or zeros of polynomials

Of course you can keep using that method for checking, but you can't get a factor, I think.

Okay, to be simple, if you can get a factor using that method, please tell me.

my step by step explanation from before doesn't make sense?

And thank you for your time explaining that to me.

*have been using that method to solve. Typo. Sorry

I just need real factors. The expression can be factorised, according to wolf

Sorry about so long attachments

I'm astonished. A question that looks as easy as simple factorization is confusing the polymaths.

attachment is about factorizing:)

when you find an answer please do inform me :) thank you!

Bt seems so useful @maheshmeghwal9.

thanx:) @ajprincess

yw.:)

If u find answer @Callisto Plz inform me:)

Hmm.... I heard of Ferrari today
"A car also comes of help to maths{LOL}"

Thanks