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bondBest ResponseYou've already chosen the best response.0
\[r ^{2}(\pi \Theta \div360\sin \Theta \div2)\]
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
Area of Segment = ½ × ( (θ × π/180)  sin θ) × r2 (when θ is in degrees)
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
u see http://www.mathsisfun.com/geometry/circlesectorsegment.html
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
but it is the area of sector I think @ParthKohli
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
we have to find segment
 one year ago
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