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tbrooks3

  • 3 years ago

find the area of segment with a 60 degree angle and 12 radius.

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  1. bond
    • 3 years ago
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    \[r ^{2}(\pi \Theta \div360-\sin \Theta \div2)\]

  2. maheshmeghwal9
    • 3 years ago
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    Area of Segment = ½ × ( (θ × π/180) - sin θ) × r2 (when θ is in degrees)

  3. bond
    • 3 years ago
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    Why 1/2 @maheshmeghwal9

  4. maheshmeghwal9
    • 3 years ago
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    u see http://www.mathsisfun.com/geometry/circle-sector-segment.html

  5. King
    • 3 years ago
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    24pi-36sqrt3?

  6. maheshmeghwal9
    • 3 years ago
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    but it is the area of sector I think @ParthKohli

  7. maheshmeghwal9
    • 3 years ago
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    we have to find segment

  8. maheshmeghwal9
    • 3 years ago
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    's area

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