anonymous 3 years ago find the area of segment with a 60 degree angle and 12 radius.

1. anonymous

$r ^{2}(\pi \Theta \div360-\sin \Theta \div2)$

2. maheshmeghwal9

Area of Segment = ½ × ( (θ × π/180) - sin θ) × r2 (when θ is in degrees)

3. anonymous

Why 1/2 @maheshmeghwal9

4. maheshmeghwal9
5. anonymous

24pi-36sqrt3?

6. maheshmeghwal9

but it is the area of sector I think @ParthKohli

7. maheshmeghwal9

we have to find segment

8. maheshmeghwal9

's area