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I will post the question in the reply box...help....

Mathematics
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how do i put fraction iin equation editor?this is not the question
\frac{numerator}{denominator} ... in latex http://www.codecogs.com/latex/eqneditor.php
\[\frac{1}{1+x ^{a-b}+x ^{b-c}} + \frac{1}{1+x ^{b-c}x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}}\]

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Prove this
prove that the above is equal to 1
\[ \frac{1}{1+x ^{a-b}+x ^{b-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} \]
yeah prove that that is equal to 1
doesn't look symmetric ... are you sure this is the one?
oh sry it is a-c instead of b-c
\[x^{b-a}=x ^{b}*x ^{-a}=x ^{b}/x ^{a}\]
My supertrick click right ... show math as => tex commands .... copy the code ... and retype the question
\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}}
\[\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} \]
\[\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} =1\]
prove the above thing
multiply \[ \frac{x^{-a}}{x^{-a}(1+x ^{a-b}+x ^{a-c})}\] do similar for others
i dont get it hw?
|dw:1339638805794:dw||dw:1339638918893:dw| Can u do the same for the others?
yeah got it!! Solved!! Thnx..@ajprincess @experimentX
Thnx... @ajprincess
U r welcome.
yw

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