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RaphaelFilgueiras Group Title

9^x-7.3^x+10=0,what is the minimum value wich made this equation correct?given(log2=0.3,log3=0.48)

  • 2 years ago
  • 2 years ago

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  1. RaphaelFilgueiras Group Title
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    3^x=u get it!

    • 2 years ago
  2. RaphaelFilgueiras Group Title
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    u²-7.u+10=0

    • 2 years ago
  3. experimentX Group Title
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    Hmm ... was that 3^x ??not 7.3^x ??

    • 2 years ago
  4. RaphaelFilgueiras Group Title
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    yes my bad

    • 2 years ago
  5. experimentX Group Title
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    i was wondering it simply was untrue ... lol

    • 2 years ago
  6. RaphaelFilgueiras Group Title
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    3^x=2

    • 2 years ago
  7. experimentX Group Title
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    x = log 2 / log 3

    • 2 years ago
  8. RaphaelFilgueiras Group Title
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    x=.3/.48

    • 2 years ago
  9. experimentX Group Title
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    I bet the minimum value that would make this equation true would be http://www.wolframalpha.com/input/?i=x^2+-+6.3x+%2B+10+%3D+0+

    • 2 years ago
  10. RaphaelFilgueiras Group Title
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    the minimum is 0.625

    • 2 years ago
  11. experimentX Group Title
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    http://www.wolframalpha.com/input/?i=x^2+-+2+sqrt%2810%29+x+%2B+10+%3D+0+

    • 2 years ago
  12. experimentX Group Title
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    Hmmm ... is it asking for two values of x??

    • 2 years ago
  13. RaphaelFilgueiras Group Title
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    no only the minimum

    • 2 years ago
  14. experimentX Group Title
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    Oh ... i guess it is solved as like you did then

    • 2 years ago
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