Here's the question you clicked on:
RaphaelFilgueiras
9^x-7.3^x+10=0,what is the minimum value wich made this equation correct?given(log2=0.3,log3=0.48)
3^x=u get it!
Hmm ... was that 3^x ??not 7.3^x ??
i was wondering it simply was untrue ... lol
I bet the minimum value that would make this equation true would be http://www.wolframalpha.com/input/?i=x^2+-+6.3x+%2B+10+%3D+0+
the minimum is 0.625
http://www.wolframalpha.com/input/?i=x^2+-+2+sqrt%2810%29+x+%2B+10+%3D+0+
Hmmm ... is it asking for two values of x??
no only the minimum
Oh ... i guess it is solved as like you did then