anonymous
  • anonymous
9^x-7.3^x+10=0,what is the minimum value wich made this equation correct?given(log2=0.3,log3=0.48)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
3^x=u get it!
anonymous
  • anonymous
u²-7.u+10=0
experimentX
  • experimentX
Hmm ... was that 3^x ??not 7.3^x ??

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More answers

anonymous
  • anonymous
yes my bad
experimentX
  • experimentX
i was wondering it simply was untrue ... lol
anonymous
  • anonymous
3^x=2
experimentX
  • experimentX
x = log 2 / log 3
anonymous
  • anonymous
x=.3/.48
experimentX
  • experimentX
I bet the minimum value that would make this equation true would be http://www.wolframalpha.com/input/?i=x^2+-+6.3x+%2B+10+%3D+0+
anonymous
  • anonymous
the minimum is 0.625
experimentX
  • experimentX
http://www.wolframalpha.com/input/?i=x^2+-+2+sqrt%2810%29+x+%2B+10+%3D+0+
experimentX
  • experimentX
Hmmm ... is it asking for two values of x??
anonymous
  • anonymous
no only the minimum
experimentX
  • experimentX
Oh ... i guess it is solved as like you did then

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