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for the problem in session 59 i can't see why t goes from 0 to pi/4 in the second part of part b..could anyone explain this for me please?
 one year ago
 one year ago
for the problem in session 59 i can't see why t goes from 0 to pi/4 in the second part of part b..could anyone explain this for me please?
 one year ago
 one year ago

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hellowBest ResponseYou've already chosen the best response.1
That part of the problem is computing the line integral of the vector over the arc of the circle. The path along the arc has been parametrized in terms of theta (solutions call it t), the angle of the position vector with respect to the xaxis. The position vector begins at (5sqrt(2), 0) which corresponds to theta = 0, and travels along the arc to (5, 5) which corresponds to theta = pi/4. (We know the angle is pi/4 because the acute angle of an isosceles right triangle is pi/4.)
 one year ago

kevinh1223Best ResponseYou've already chosen the best response.0
Thank you very much!
 one year ago
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