A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Professor Bartlett teaches a class of 11 students. She has a visually impaired student, Louise, who must sit in the front row next to her tutor, who is also a member of this class. Assume that the front row has eight chairs, and the tutor must be seated to the right of Louise. How many different ways can professor Bartlett assign students to sit in the first row?
anonymous
 4 years ago
Professor Bartlett teaches a class of 11 students. She has a visually impaired student, Louise, who must sit in the front row next to her tutor, who is also a member of this class. Assume that the front row has eight chairs, and the tutor must be seated to the right of Louise. How many different ways can professor Bartlett assign students to sit in the first row?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 help? :)

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1A big key phrase here is that "the tutor must be seated to the right of Louise", so if T is the tutor and L is Louise, then you can only have LT and NOT TL So basically LT is one person since you can't a) separate the two AND b) you can't reorder it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 6 spaces left right

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1So instead of 11 students to order, you really have 112+1 = 10 students to order since you're combining two students to form one "student'

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1There are 8 chairs in the front, but 2 are taken up and combined into one "chair" so to speak. So there are really 82+1 = 7 "chairs" in the front row.

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1So it's really 10 P 7

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.15040 is 7! or 7 P 7, so no

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.110 P 7 = (10!)/((107)!)

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1you're welcome
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.