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A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?

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15 meters?

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Other answers:

why not just 1? i mean it's simpler isnt it?
total dist = 2d total time = d/5 + d/3 = 8d/15 so avg speed = 2d/(8d/15) so @A.Avinash_Goutham was right!! yet again! :D
so it will be 30/8 seconds?
When the distance is fixed, just find the harmonic mean.
i mean m/s
what does harmonic mean mean again?
For two number a and b the harmonic mean is given by 2ab/(a+b)
Speed = (distance traveled)/(time taken) Total distance traveled = 0 Speed = 0 m/s
where a and b are...?
the given values?
speed = distance / time if distance = 1 5 = 1 / 0.2 also 3 = 1 / 0.3333 average speed = 2 / 0.53333
a=5 and b =3 or vice-versa
its 3.75 m/s 4 is wrong
if it's equal " time " u shud use........arithmetic nd equal dist u shud use..........harmonic
this is effective everytime d is equal?
total distance /total time travelled
Yes lgba and when time is equal find the arithmetic mean.
arithmetic mean is..?
2d ----------- d +d -- ---- 5 3 2d --------- 8d ------ 15 2 ---- 8 ------ 15
2 ---- 8 --- 15 15 ---- 4
lol yeah i got that part =)) btw...a follow-up question is what is the average velocity...the book says it because displacement is 0?
yeah it is zero
yes,,because disp is 0..
but its speed written in the question???
the first question was average speed
yeah but there is a difference displacement can come to zero bot distance cannot u should mention adds up whether how many time come and go from same point asdisplacement get zero
distance adds up*
lol really? at 5m/s ?
what? o.O
A person walks first at constant speed of 5.00 m/s <== that guy must be one heck of a power walker haha

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