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lgbasallote
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A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?
 2 years ago
 2 years ago
lgbasallote Group Title
A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?
 2 years ago
 2 years ago

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A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
:/
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
30/8
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
15 meters?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
why not just 1? i mean it's simpler isnt it?
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
total dist = 2d total time = d/5 + d/3 = 8d/15 so avg speed = 2d/(8d/15) so @A.Avinash_Goutham was right!! yet again! :D
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so it will be 30/8 seconds?
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.3
When the distance is fixed, just find the harmonic mean.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i mean m/s
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
what does harmonic mean mean again?
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.3
For two number a and b the harmonic mean is given by 2ab/(a+b)
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Speed = (distance traveled)/(time taken) Total distance traveled = 0 Speed = 0 m/s
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
where a and b are...?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
the given values?
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
speed = distance / time if distance = 1 5 = 1 / 0.2 also 3 = 1 / 0.3333 average speed = 2 / 0.53333
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.3
a=5 and b =3 or viceversa
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
its 3.75 m/s 4 is wrong
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
if it's equal " time " u shud use........arithmetic nd equal dist u shud use..........harmonic
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
this is effective everytime d is equal?
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
total distance /total time travelled
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.3
Yes lgba and when time is equal find the arithmetic mean.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
arithmetic mean is..?
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
2d  d +d   5 3 2d  8d  15 2  8  15
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
2  8  15 15  4
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
lol yeah i got that part =)) btw...a followup question is what is the average velocity...the book says zero...is it because displacement is 0?
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
yeah it is zero
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
yes,,because disp is 0..
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
but its speed written in the question???
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
the first question was average speed
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
yeah but there is a difference displacement can come to zero bot distance cannot u should mention adds up whether how many time come and go from same point asdisplacement get zero
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.0
distance adds up*
 2 years ago

javawarrior Group TitleBest ResponseYou've already chosen the best response.0
lol really? at 5m/s ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
what? o.O
 2 years ago

javawarrior Group TitleBest ResponseYou've already chosen the best response.0
A person walks first at constant speed of 5.00 m/s <== that guy must be one heck of a power walker haha
 2 years ago
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