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lgbasallote
 3 years ago
A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?
lgbasallote
 3 years ago
A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?

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lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0why not just 1? i mean it's simpler isnt it?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0total dist = 2d total time = d/5 + d/3 = 8d/15 so avg speed = 2d/(8d/15) so @A.Avinash_Goutham was right!! yet again! :D

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0so it will be 30/8 seconds?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3When the distance is fixed, just find the harmonic mean.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0what does harmonic mean mean again?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3For two number a and b the harmonic mean is given by 2ab/(a+b)

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Speed = (distance traveled)/(time taken) Total distance traveled = 0 Speed = 0 m/s

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0where a and b are...?

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0speed = distance / time if distance = 1 5 = 1 / 0.2 also 3 = 1 / 0.3333 average speed = 2 / 0.53333

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3a=5 and b =3 or viceversa

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.0its 3.75 m/s 4 is wrong

A.Avinash_Goutham
 3 years ago
Best ResponseYou've already chosen the best response.0if it's equal " time " u shud use........arithmetic nd equal dist u shud use..........harmonic

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0this is effective everytime d is equal?

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.0total distance /total time travelled

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.3Yes lgba and when time is equal find the arithmetic mean.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0arithmetic mean is..?

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.02d  d +d   5 3 2d  8d  15 2  8  15

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.02  8  15 15  4

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0lol yeah i got that part =)) btw...a followup question is what is the average velocity...the book says zero...is it because displacement is 0?

A.Avinash_Goutham
 3 years ago
Best ResponseYou've already chosen the best response.0yeah it is zero

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0yes,,because disp is 0..

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.0but its speed written in the question???

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0the first question was average speed

Nick_Black
 3 years ago
Best ResponseYou've already chosen the best response.0yeah but there is a difference displacement can come to zero bot distance cannot u should mention adds up whether how many time come and go from same point asdisplacement get zero

javawarrior
 3 years ago
Best ResponseYou've already chosen the best response.0lol really? at 5m/s ?

javawarrior
 3 years ago
Best ResponseYou've already chosen the best response.0A person walks first at constant speed of 5.00 m/s <== that guy must be one heck of a power walker haha
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