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shahzadjalbani

  • 3 years ago

{x+2 0<x<1 f(x)={x 1< or = x<2 {x+5 2< or = x<3 Is the function is continuous or not? Explain.

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  1. yakeyglee
    • 3 years ago
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    At the boundaries of the pieces (i.e., \(x=1\) and \(x=2\)), see if the adjacent pieces align up.

  2. shahzadjalbani
    • 3 years ago
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    Explain @yakeyglee

  3. shahzadjalbani
    • 3 years ago
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    @angela210793 @AccessDenied @Agent_Sniffles @Austin_Rain @physicsme @SmoothMath

  4. yakeyglee
    • 3 years ago
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    \(x+2\) and \(x\) are both adjacent to \(x=1\) (it's where one ends and the other beings). Do they have the same value at that point?

  5. shahzadjalbani
    • 3 years ago
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    @Outkast3r09 @vikayefremova @lalaly @LokoRay

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