Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lgbasallote
Group Title
An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?
 2 years ago
 2 years ago
lgbasallote Group Title
An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?
 2 years ago
 2 years ago

This Question is Closed

javawarrior Group TitleBest ResponseYou've already chosen the best response.0
lol in first
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
wrong group
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
isnt it math?
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.3
What is his/her initial medalage? does he/she start from 0?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
but isnt this an ordinary math problem too?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i mean the basic concepts still come in play
 2 years ago

javawarrior Group TitleBest ResponseYou've already chosen the best response.0
its both, physics and math.Arguably physics is nothing without math though :)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
lol can we just teach me how to solve this? :p
 2 years ago

javawarrior Group TitleBest ResponseYou've already chosen the best response.0
well first of all, his acceleration cant be 2 medals/day a = v / t since you postulated that v = 40 per day a = 40 per day because a = delta V / delta t
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
but my book says 50 days o.O
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.3
I would consider it an initial velocity. Its like saying a car is going at 40 ft/s, and accelerating at 2 ft/s^2.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
yeah that'swhat i think too
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.3
To solve the problem use the formula:\[d = x_0+v_0t+\frac{1}{2}at^2\]Set d to 4500, intial position to 0, intiial velocity to 40, and acceleration to 2. Solve for t.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so 4500 = 40t + t^2?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm yep i think that gives 50thanks
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.