## lgbasallote 3 years ago An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?

1. javawarrior

lol in first

2. Tomas.A

wrong group

3. lgbasallote

isnt it math?

4. joemath314159

What is his/her initial medalage? does he/she start from 0?

5. Tomas.A

physics

6. lgbasallote

yup 0

7. lgbasallote

but isnt this an ordinary math problem too?

8. lgbasallote

i mean the basic concepts still come in play

9. javawarrior

its both, physics and math.Arguably physics is nothing without math though :)

10. lgbasallote

lol can we just teach me how to solve this? :p

11. javawarrior

well first of all, his acceleration cant be 2 medals/day a = v / t since you postulated that v = 40 per day a = 40 per day because a = delta V / delta t

12. lgbasallote

but my book says 50 days o.O

13. joemath314159

I would consider it an initial velocity. Its like saying a car is going at 40 ft/s, and accelerating at 2 ft/s^2.

14. lgbasallote

yeah that'swhat i think too

15. joemath314159

To solve the problem use the formula:$d = x_0+v_0t+\frac{1}{2}at^2$Set d to 4500, intial position to 0, intiial velocity to 40, and acceleration to 2. Solve for t.

16. lgbasallote

so 4500 = 40t + t^2?

17. joemath314159

yep

18. lgbasallote

hmm yep i think that gives 50thanks