## lgbasallote Group Title An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank? 2 years ago 2 years ago

1. javawarrior Group Title

lol in first

2. Tomas.A Group Title

wrong group

3. lgbasallote Group Title

isnt it math?

4. joemath314159 Group Title

What is his/her initial medalage? does he/she start from 0?

5. Tomas.A Group Title

physics

6. lgbasallote Group Title

yup 0

7. lgbasallote Group Title

but isnt this an ordinary math problem too?

8. lgbasallote Group Title

i mean the basic concepts still come in play

9. javawarrior Group Title

its both, physics and math.Arguably physics is nothing without math though :)

10. lgbasallote Group Title

lol can we just teach me how to solve this? :p

11. javawarrior Group Title

well first of all, his acceleration cant be 2 medals/day a = v / t since you postulated that v = 40 per day a = 40 per day because a = delta V / delta t

12. lgbasallote Group Title

but my book says 50 days o.O

13. joemath314159 Group Title

I would consider it an initial velocity. Its like saying a car is going at 40 ft/s, and accelerating at 2 ft/s^2.

14. lgbasallote Group Title

yeah that'swhat i think too

15. joemath314159 Group Title

To solve the problem use the formula:$d = x_0+v_0t+\frac{1}{2}at^2$Set d to 4500, intial position to 0, intiial velocity to 40, and acceleration to 2. Solve for t.

16. lgbasallote Group Title

so 4500 = 40t + t^2?

17. joemath314159 Group Title

yep

18. lgbasallote Group Title

hmm yep i think that gives 50thanks