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anonymous
 3 years ago
An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?
anonymous
 3 years ago
An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is his/her initial medalage? does he/she start from 0?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but isnt this an ordinary math problem too?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean the basic concepts still come in play

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its both, physics and math.Arguably physics is nothing without math though :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol can we just teach me how to solve this? :p

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well first of all, his acceleration cant be 2 medals/day a = v / t since you postulated that v = 40 per day a = 40 per day because a = delta V / delta t

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but my book says 50 days o.O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I would consider it an initial velocity. Its like saying a car is going at 40 ft/s, and accelerating at 2 ft/s^2.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah that'swhat i think too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0To solve the problem use the formula:\[d = x_0+v_0t+\frac{1}{2}at^2\]Set d to 4500, intial position to 0, intiial velocity to 40, and acceleration to 2. Solve for t.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm yep i think that gives 50thanks
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