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lgbasallote

  • 3 years ago

An OpenStudy user's speed is 40 medals per day and his acceleration is 2 medal/day^2. If it takes 4,500 medals to reach the Legend rank, how many days will it take for him to reach the rank?

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  1. javawarrior
    • 3 years ago
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    lol in first

  2. Tomas.A
    • 3 years ago
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    wrong group

  3. lgbasallote
    • 3 years ago
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    isnt it math?

  4. joemath314159
    • 3 years ago
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    What is his/her initial medalage? does he/she start from 0?

  5. Tomas.A
    • 3 years ago
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    physics

  6. lgbasallote
    • 3 years ago
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    yup 0

  7. lgbasallote
    • 3 years ago
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    but isnt this an ordinary math problem too?

  8. lgbasallote
    • 3 years ago
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    i mean the basic concepts still come in play

  9. javawarrior
    • 3 years ago
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    its both, physics and math.Arguably physics is nothing without math though :)

  10. lgbasallote
    • 3 years ago
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    lol can we just teach me how to solve this? :p

  11. javawarrior
    • 3 years ago
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    well first of all, his acceleration cant be 2 medals/day a = v / t since you postulated that v = 40 per day a = 40 per day because a = delta V / delta t

  12. lgbasallote
    • 3 years ago
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    but my book says 50 days o.O

  13. joemath314159
    • 3 years ago
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    I would consider it an initial velocity. Its like saying a car is going at 40 ft/s, and accelerating at 2 ft/s^2.

  14. lgbasallote
    • 3 years ago
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    yeah that'swhat i think too

  15. joemath314159
    • 3 years ago
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    To solve the problem use the formula:\[d = x_0+v_0t+\frac{1}{2}at^2\]Set d to 4500, intial position to 0, intiial velocity to 40, and acceleration to 2. Solve for t.

  16. lgbasallote
    • 3 years ago
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    so 4500 = 40t + t^2?

  17. joemath314159
    • 3 years ago
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    yep

  18. lgbasallote
    • 3 years ago
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    hmm yep i think that gives 50thanks

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