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soccergal12

The effectiveness of an anesthetic t minutes after entering the blood stream is given by: e(t) = 2/25 ( 5 + 3t + 3t^2 – t^3) (a) find the average rate of change of the drug effectiveness between t = 1 and t = 4 (b) find the instantaneous rates of change of the drug effectiveness at time = 1 and at time = 4. in one sentence, interpret the meaning of this value.

  • one year ago
  • one year ago

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  1. ganeshie8
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    average rate of change between [1,4] = \[\left[ e(4) - e(1) \right] / \left[ 4 - 1 \right]\]

    • one year ago
  2. soccergal12
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    By using that, would i get -6/25 as my answer?

    • one year ago
  3. ganeshie8
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    thats correct for average rate of change. you have edited the question... now the question is talking about instantaneous rates of change, you need to use derivatives for (b)

    • one year ago
  4. soccergal12
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    yes, i used the derivatives and go the answers, on number is negative and the other is positive. it says to interpret the meaning of this value. what would i say?

    • one year ago
  5. ganeshie8
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    that means, between t =1 and t =4, the anesthetic is becoming 0. and the patient gets up... makes sense ?

    • one year ago
  6. soccergal12
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    yeah! that does. thanks a lot :)

    • one year ago
  7. soccergal12
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    one more question. would the answers need units?

    • one year ago
  8. ganeshie8
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    hey hold on. it doesnt mean that at all lol.. it means this : between t =1 and t =4, the anesthetic effect stopped INCREASING, became zero, and starts DECREASING. patient may not get up yet.. understood ? no units in the question right. so no need to bother, but if you wanto guess, the time must be in hours. as seconds are too small. and days are too long...

    • one year ago
  9. ganeshie8
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    after t= 4, patient may be lying unconscious, but the anesthetic effect has started decreasing some time ago after t=1.. hope it is clear

    • one year ago
  10. soccergal12
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    haha, yes. that makes sense. thanks again.

    • one year ago
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