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ParthKohli
Group Title
OpenStudy in real life problem:
A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name?
Assume that all letters are small.
 2 years ago
 2 years ago
ParthKohli Group Title
OpenStudy in real life problem: A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name? Assume that all letters are small.
 2 years ago
 2 years ago

This Question is Closed

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Hint: the first and last are fixed values.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
The solution would be posted in a while.
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
9 * 26^8 * 10
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
How did you get the answer? explain my friends
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.0
satellite73 but don't know combination
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
@ParthKohli why did u post the answer so fast ??
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
You are forgetting there are 9 possible arrangements.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
lol but satellite73 is correct =))
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
i waas going to xplain?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
9 possible rearrangements?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Dw lol this was an easy problem.. I'll post a much more difficult one after this
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
@ParthKohli bt pls post the soln only after sufficient time
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
I have deleted it.
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
25P8 * 10 = 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 10
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
nah ..nw evryone have read it :(
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
No wait... letters can repeat.. I didn't say they can't
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
# x x x x x x x x is not the same as x # x x x x x x x
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
And then 2 numbers. I guess I framed the problem wrong.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
It's like s x x x x x x x x # 3
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
I had taken satellite as an example, I'm sorry I framed it wrong though
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Sorry for that sir.
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
number of English alphbet = 26 number of number = 10 The first and the last one is fixed that is s _ _ _ _ _ _ _ 3 Where _ can be a letter or a number Case one: the number is the second one, that is s (number) (letter)x6 3 Number of combinations = 1 times 10 times 26^6 times 1 = 10 x 26^6 Case two, the number is the third one, that is s (letter) (number) (letter)x5 3 = 1 times 26 times 10 times 26^5 times1 = 10 x 26^6 ... Case seven, the number is the 8th one, that is s (letter)x6 (number) 3 = 1 times 26^6 times 10 times 1 = 26^6 times 1 Add all the cases, P required = 7 x 10 x 26^6 This must be wrong... I hardly solve a probability/combination question correctly
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
@Callisto can you give a medal to slaibak?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Thanks :)
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
You can give the medal to slaibak :)
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
ya @Callisto is going to give me :P
 2 years ago
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