OpenStudy in real life problem:
A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name?
Assume that all letters are small.
Stacey Warren - Expert brainly.com
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No wait... letters can repeat.. I didn't say they can't
# x x x x x x x x
is not the same as
x # x x x x x x x
And then 2 numbers. I guess I framed the problem wrong.
It's like s x x x x x x x x # 3
I had taken satellite as an example, I'm sorry I framed it wrong though
oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.
Sorry for that sir.
number of English alphbet = 26
number of number = 10
The first and the last one is fixed that is s _ _ _ _ _ _ _ 3
Where _ can be a letter or a number
the number is the second one, that is s (number) (letter)x6 3
Number of combinations
= 1 times 10 times 26^6 times 1
= 10 x 26^6
Case two, the number is the third one, that is s (letter) (number) (letter)x5 3
= 1 times 26 times 10 times 26^5 times1
= 10 x 26^6
Case seven, the number is the 8th one, that is s (letter)x6 (number) 3
= 1 times 26^6 times 10 times 1
= 26^6 times 1
Add all the cases,
P required = 7 x 10 x 26^6
This must be wrong... I hardly solve a probability/combination question correctly