ParthKohli
  • ParthKohli
OpenStudy in real life problem: A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name? Assume that all letters are small.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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ParthKohli
  • ParthKohli
Hint: the first and last are fixed values.
ParthKohli
  • ParthKohli
The solution would be posted in a while.
slaaibak
  • slaaibak
9 * 26^8 * 10

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More answers

ParthKohli
  • ParthKohli
How did you get the answer? explain my friends
maheshmeghwal9
  • maheshmeghwal9
satellite73 but don't know combination
AravindG
  • AravindG
26^8 *10
AravindG
  • AravindG
@ParthKohli why did u post the answer so fast ??
slaaibak
  • slaaibak
You are forgetting there are 9 possible arrangements.
ParthKohli
  • ParthKohli
lol but satellite73 is correct =))
AravindG
  • AravindG
i waas going to xplain?
ParthKohli
  • ParthKohli
9 possible rearrangements?
ParthKohli
  • ParthKohli
Dw lol this was an easy problem.. I'll post a much more difficult one after this
AravindG
  • AravindG
@ParthKohli bt pls post the soln only after sufficient time
ParthKohli
  • ParthKohli
I have deleted it.
kropot72
  • kropot72
25P8 * 10 = 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 10
AravindG
  • AravindG
nah ..nw evryone have read it :(
ParthKohli
  • ParthKohli
No wait... letters can repeat.. I didn't say they can't
slaaibak
  • slaaibak
# x x x x x x x x is not the same as x # x x x x x x x
ParthKohli
  • ParthKohli
And then 2 numbers. I guess I framed the problem wrong.
ParthKohli
  • ParthKohli
It's like s x x x x x x x x # 3
ParthKohli
  • ParthKohli
I had taken satellite as an example, I'm sorry I framed it wrong though
slaaibak
  • slaaibak
oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.
ParthKohli
  • ParthKohli
Sorry for that sir.
Callisto
  • Callisto
number of English alphbet = 26 number of number = 10 The first and the last one is fixed that is s _ _ _ _ _ _ _ 3 Where _ can be a letter or a number Case one: the number is the second one, that is s (number) (letter)x6 3 Number of combinations = 1 times 10 times 26^6 times 1 = 10 x 26^6 Case two, the number is the third one, that is s (letter) (number) (letter)x5 3 = 1 times 26 times 10 times 26^5 times1 = 10 x 26^6 ... Case seven, the number is the 8th one, that is s (letter)x6 (number) 3 = 1 times 26^6 times 10 times 1 = 26^6 times 1 Add all the cases, P required = 7 x 10 x 26^6 This must be wrong... I hardly solve a probability/combination question correctly
ParthKohli
  • ParthKohli
@Callisto can you give a medal to slaibak?
AravindG
  • AravindG
i will :)
ParthKohli
  • ParthKohli
Thanks :)
Callisto
  • Callisto
You can give the medal to slaibak :)
AravindG
  • AravindG
ya @Callisto is going to give me :P

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