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OpenStudy in real life problem:
A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name?
Assume that all letters are small.
 one year ago
 one year ago
OpenStudy in real life problem: A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name? Assume that all letters are small.
 one year ago
 one year ago

This Question is Closed

ParthKohliBest ResponseYou've already chosen the best response.1
Hint: the first and last are fixed values.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The solution would be posted in a while.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
How did you get the answer? explain my friends
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.0
satellite73 but don't know combination
 one year ago

AravindGBest ResponseYou've already chosen the best response.1
@ParthKohli why did u post the answer so fast ??
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
You are forgetting there are 9 possible arrangements.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
lol but satellite73 is correct =))
 one year ago

AravindGBest ResponseYou've already chosen the best response.1
i waas going to xplain?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
9 possible rearrangements?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Dw lol this was an easy problem.. I'll post a much more difficult one after this
 one year ago

AravindGBest ResponseYou've already chosen the best response.1
@ParthKohli bt pls post the soln only after sufficient time
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
25P8 * 10 = 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 10
 one year ago

AravindGBest ResponseYou've already chosen the best response.1
nah ..nw evryone have read it :(
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
No wait... letters can repeat.. I didn't say they can't
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
# x x x x x x x x is not the same as x # x x x x x x x
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
And then 2 numbers. I guess I framed the problem wrong.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
It's like s x x x x x x x x # 3
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I had taken satellite as an example, I'm sorry I framed it wrong though
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Sorry for that sir.
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
number of English alphbet = 26 number of number = 10 The first and the last one is fixed that is s _ _ _ _ _ _ _ 3 Where _ can be a letter or a number Case one: the number is the second one, that is s (number) (letter)x6 3 Number of combinations = 1 times 10 times 26^6 times 1 = 10 x 26^6 Case two, the number is the third one, that is s (letter) (number) (letter)x5 3 = 1 times 26 times 10 times 26^5 times1 = 10 x 26^6 ... Case seven, the number is the 8th one, that is s (letter)x6 (number) 3 = 1 times 26^6 times 10 times 1 = 26^6 times 1 Add all the cases, P required = 7 x 10 x 26^6 This must be wrong... I hardly solve a probability/combination question correctly
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
@Callisto can you give a medal to slaibak?
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
You can give the medal to slaibak :)
 one year ago

AravindGBest ResponseYou've already chosen the best response.1
ya @Callisto is going to give me :P
 one year ago
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