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ParthKohli Group Title

OpenStudy in real life problem: A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name? Assume that all letters are small.

  • 2 years ago
  • 2 years ago

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  1. ParthKohli Group Title
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    Hint: the first and last are fixed values.

    • 2 years ago
  2. ParthKohli Group Title
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    The solution would be posted in a while.

    • 2 years ago
  3. slaaibak Group Title
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    9 * 26^8 * 10

    • 2 years ago
  4. ParthKohli Group Title
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    How did you get the answer? explain my friends

    • 2 years ago
  5. maheshmeghwal9 Group Title
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    satellite73 but don't know combination

    • 2 years ago
  6. AravindG Group Title
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    26^8 *10

    • 2 years ago
  7. AravindG Group Title
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    @ParthKohli why did u post the answer so fast ??

    • 2 years ago
  8. slaaibak Group Title
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    You are forgetting there are 9 possible arrangements.

    • 2 years ago
  9. ParthKohli Group Title
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    lol but satellite73 is correct =))

    • 2 years ago
  10. AravindG Group Title
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    i waas going to xplain?

    • 2 years ago
  11. ParthKohli Group Title
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    9 possible rearrangements?

    • 2 years ago
  12. ParthKohli Group Title
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    Dw lol this was an easy problem.. I'll post a much more difficult one after this

    • 2 years ago
  13. AravindG Group Title
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    @ParthKohli bt pls post the soln only after sufficient time

    • 2 years ago
  14. ParthKohli Group Title
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    I have deleted it.

    • 2 years ago
  15. kropot72 Group Title
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    25P8 * 10 = 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 10

    • 2 years ago
  16. AravindG Group Title
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    nah ..nw evryone have read it :(

    • 2 years ago
  17. ParthKohli Group Title
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    No wait... letters can repeat.. I didn't say they can't

    • 2 years ago
  18. slaaibak Group Title
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    # x x x x x x x x is not the same as x # x x x x x x x

    • 2 years ago
  19. ParthKohli Group Title
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    And then 2 numbers. I guess I framed the problem wrong.

    • 2 years ago
  20. ParthKohli Group Title
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    It's like s x x x x x x x x # 3

    • 2 years ago
  21. ParthKohli Group Title
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    I had taken satellite as an example, I'm sorry I framed it wrong though

    • 2 years ago
  22. slaaibak Group Title
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    oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.

    • 2 years ago
  23. ParthKohli Group Title
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    Sorry for that sir.

    • 2 years ago
  24. Callisto Group Title
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    number of English alphbet = 26 number of number = 10 The first and the last one is fixed that is s _ _ _ _ _ _ _ 3 Where _ can be a letter or a number Case one: the number is the second one, that is s (number) (letter)x6 3 Number of combinations = 1 times 10 times 26^6 times 1 = 10 x 26^6 Case two, the number is the third one, that is s (letter) (number) (letter)x5 3 = 1 times 26 times 10 times 26^5 times1 = 10 x 26^6 ... Case seven, the number is the 8th one, that is s (letter)x6 (number) 3 = 1 times 26^6 times 10 times 1 = 26^6 times 1 Add all the cases, P required = 7 x 10 x 26^6 This must be wrong... I hardly solve a probability/combination question correctly

    • 2 years ago
  25. ParthKohli Group Title
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    @Callisto can you give a medal to slaibak?

    • 2 years ago
  26. AravindG Group Title
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    i will :)

    • 2 years ago
  27. ParthKohli Group Title
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    Thanks :)

    • 2 years ago
  28. Callisto Group Title
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    You can give the medal to slaibak :)

    • 2 years ago
  29. AravindG Group Title
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    ya @Callisto is going to give me :P

    • 2 years ago
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