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ParthKohli

OpenStudy in real life problem: A user has 9 letters and then 2 numbers in his/her username. If you know that the first letter is 's' and the last number is '3', then how many combinations are possible for the name? Assume that all letters are small.

  • one year ago
  • one year ago

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  1. ParthKohli
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    Hint: the first and last are fixed values.

    • one year ago
  2. ParthKohli
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    The solution would be posted in a while.

    • one year ago
  3. slaaibak
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    9 * 26^8 * 10

    • one year ago
  4. ParthKohli
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    How did you get the answer? explain my friends

    • one year ago
  5. maheshmeghwal9
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    satellite73 but don't know combination

    • one year ago
  6. AravindG
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    26^8 *10

    • one year ago
  7. AravindG
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    @ParthKohli why did u post the answer so fast ??

    • one year ago
  8. slaaibak
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    You are forgetting there are 9 possible arrangements.

    • one year ago
  9. ParthKohli
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    lol but satellite73 is correct =))

    • one year ago
  10. AravindG
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    i waas going to xplain?

    • one year ago
  11. ParthKohli
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    9 possible rearrangements?

    • one year ago
  12. ParthKohli
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    Dw lol this was an easy problem.. I'll post a much more difficult one after this

    • one year ago
  13. AravindG
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    @ParthKohli bt pls post the soln only after sufficient time

    • one year ago
  14. ParthKohli
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    I have deleted it.

    • one year ago
  15. kropot72
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    25P8 * 10 = 25 * 24 * 23 * 22 * 21 * 20 * 19 * 18 * 10

    • one year ago
  16. AravindG
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    nah ..nw evryone have read it :(

    • one year ago
  17. ParthKohli
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    No wait... letters can repeat.. I didn't say they can't

    • one year ago
  18. slaaibak
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    # x x x x x x x x is not the same as x # x x x x x x x

    • one year ago
  19. ParthKohli
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    And then 2 numbers. I guess I framed the problem wrong.

    • one year ago
  20. ParthKohli
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    It's like s x x x x x x x x # 3

    • one year ago
  21. ParthKohli
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    I had taken satellite as an example, I'm sorry I framed it wrong though

    • one year ago
  22. slaaibak
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    oh... yeah you should state clearly that the numbers appear at the end, that was a bit ambiguous.. if the numbers should be in the last two spots, its 26^8 * 10, yes.

    • one year ago
  23. ParthKohli
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    Sorry for that sir.

    • one year ago
  24. Callisto
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    number of English alphbet = 26 number of number = 10 The first and the last one is fixed that is s _ _ _ _ _ _ _ 3 Where _ can be a letter or a number Case one: the number is the second one, that is s (number) (letter)x6 3 Number of combinations = 1 times 10 times 26^6 times 1 = 10 x 26^6 Case two, the number is the third one, that is s (letter) (number) (letter)x5 3 = 1 times 26 times 10 times 26^5 times1 = 10 x 26^6 ... Case seven, the number is the 8th one, that is s (letter)x6 (number) 3 = 1 times 26^6 times 10 times 1 = 26^6 times 1 Add all the cases, P required = 7 x 10 x 26^6 This must be wrong... I hardly solve a probability/combination question correctly

    • one year ago
  25. ParthKohli
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    @Callisto can you give a medal to slaibak?

    • one year ago
  26. AravindG
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    i will :)

    • one year ago
  27. ParthKohli
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    Thanks :)

    • one year ago
  28. Callisto
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    You can give the medal to slaibak :)

    • one year ago
  29. AravindG
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    ya @Callisto is going to give me :P

    • one year ago
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