Subtract.
[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]
Simplify your answer as much as possible

- anonymous

Subtract.
[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]
Simplify your answer as much as possible

- schrodinger

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- anonymous

Help is greatly appreciated

- saifoo.khan

Find LCD.

- anonymous

dont know how to do this :/

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## More answers

- saifoo.khan

@Tomas.A . help.

- anonymous

that would be great if you could help!

- saifoo.khan

Ok.

- anonymous

\[[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]\]

- saifoo.khan

|dw:1339902311825:dw|it's like that right?

- anonymous

yeah

- saifoo.khan

So what do u think of LCD?

- anonymous

im not really sure, i suck at fractions :/

- saifoo.khan

dont worry about fractions. it's easy.
you have two things:
6c^3*d and 8b^2*d^2
open up, the
numbers: 6,8
variables: c^3, d
variables: b^2 d^2
agree?

- anonymous

Right

- saifoo.khan

So the LCD will be,
6*8 = 48
for variables,
c^3 and b^2.
now what about d and d^2
we always take the bigger term,
so we will take d^2.
Therefore our LCD will be,
48*c^3*b^2*d^2

- anonymous

oh okay perfect, then what??

- saifoo.khan

now,
|dw:1339902810873:dw|Do you get this step?

- anonymous

for the most part, yeah

- saifoo.khan

What we have to do is, we have to make the denominators same as LCD.
so we had 6c^3d.. and we have to make it as 48c^3b^2d^2
we have to multiply 6c^3d with something to make it as 48c^3b^2d^2
so we multiplied by 8b^2d.

- anonymous

oh okay and for the numerator??

- saifoo.khan

When we multiply that for denominator, we multiply the same thing with numerator.

- anonymous

how do i multiply that out though? :/

- saifoo.khan

\[\Large \frac{48c^3b^2d^2}{6c^3d} \to8b^2d.\]

- anonymous

woah..thats the numerator?

- saifoo.khan

Yes sir.

- saifoo.khan

that's what u have to multiply with numerator.

- anonymous

i must be driving you crazy, lol, but i dont get how to multiply it and simplify afterwards..
:/

- saifoo.khan

C'mon. chill up!

- saifoo.khan

and tell me where are u stuck.

- anonymous

i got the denominator, now i need to get the numerator and then simplify. i know what to multiply but i dont know how :/ i get some super long answer with a bunch of variables

- saifoo.khan

whatever you multiply with denominator.. you have to multiply the same thing with the numerator.

- anonymous

yeah

- saifoo.khan

So now,
u(8b^2d) = 8b^2du

- anonymous

so, 8b^2du - 3c^3w^3?

- saifoo.khan

you forgot to multiply the right denominator and then the numerator.

- saifoo.khan

you did it with left one right? now do it with right one as well.

- anonymous

so it would be 6c^3*d(3c^3*w^3)?

- saifoo.khan

No. since the denominators are different. we will do something like:|dw:1339903883124:dw|

- anonymous

ohh
okay and once i get that, the top would be 8b^2du-18c^6w^3?

- saifoo.khan

Yes sir.
that answer over \[\Large \frac{8b^2du-18c^6w^3}{48c^3 b^2 d^2}\]

- anonymous

okay and does that get simplified further??

- saifoo.khan

Yes. you can take commons.

- anonymous

like the b^2?

- saifoo.khan

b^2 is not in the second term.

- anonymous

ahh :( idk how then

- saifoo.khan

HINT: 8 and 18

- anonymous

-10b^2*d*u*c^6*w^3/48c^3*b^2*d^2??

- saifoo.khan

umm... no

- anonymous

:/

- saifoo.khan

|dw:1339904363228:dw|

- anonymous

then theres more left to simplify or no?

- saifoo.khan

http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG
lol.

- anonymous

lol okay, thank you SOOOO much!!

- saifoo.khan

No problem! (:

- anonymous

:) thanks again!

- saifoo.khan

Welcome.

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