anonymous
  • anonymous
Subtract. [(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)] Simplify your answer as much as possible
Mathematics
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anonymous
  • anonymous
Subtract. [(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)] Simplify your answer as much as possible
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Help is greatly appreciated
saifoo.khan
  • saifoo.khan
Find LCD.
anonymous
  • anonymous
dont know how to do this :/

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saifoo.khan
  • saifoo.khan
@Tomas.A . help.
anonymous
  • anonymous
that would be great if you could help!
saifoo.khan
  • saifoo.khan
Ok.
anonymous
  • anonymous
\[[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]\]
saifoo.khan
  • saifoo.khan
|dw:1339902311825:dw|it's like that right?
anonymous
  • anonymous
yeah
saifoo.khan
  • saifoo.khan
So what do u think of LCD?
anonymous
  • anonymous
im not really sure, i suck at fractions :/
saifoo.khan
  • saifoo.khan
dont worry about fractions. it's easy. you have two things: 6c^3*d and 8b^2*d^2 open up, the numbers: 6,8 variables: c^3, d variables: b^2 d^2 agree?
anonymous
  • anonymous
Right
saifoo.khan
  • saifoo.khan
So the LCD will be, 6*8 = 48 for variables, c^3 and b^2. now what about d and d^2 we always take the bigger term, so we will take d^2. Therefore our LCD will be, 48*c^3*b^2*d^2
anonymous
  • anonymous
oh okay perfect, then what??
saifoo.khan
  • saifoo.khan
now, |dw:1339902810873:dw|Do you get this step?
anonymous
  • anonymous
for the most part, yeah
saifoo.khan
  • saifoo.khan
What we have to do is, we have to make the denominators same as LCD. so we had 6c^3d.. and we have to make it as 48c^3b^2d^2 we have to multiply 6c^3d with something to make it as 48c^3b^2d^2 so we multiplied by 8b^2d.
anonymous
  • anonymous
oh okay and for the numerator??
saifoo.khan
  • saifoo.khan
When we multiply that for denominator, we multiply the same thing with numerator.
anonymous
  • anonymous
how do i multiply that out though? :/
saifoo.khan
  • saifoo.khan
\[\Large \frac{48c^3b^2d^2}{6c^3d} \to8b^2d.\]
anonymous
  • anonymous
woah..thats the numerator?
saifoo.khan
  • saifoo.khan
Yes sir.
saifoo.khan
  • saifoo.khan
that's what u have to multiply with numerator.
anonymous
  • anonymous
i must be driving you crazy, lol, but i dont get how to multiply it and simplify afterwards.. :/
saifoo.khan
  • saifoo.khan
C'mon. chill up!
saifoo.khan
  • saifoo.khan
and tell me where are u stuck.
anonymous
  • anonymous
i got the denominator, now i need to get the numerator and then simplify. i know what to multiply but i dont know how :/ i get some super long answer with a bunch of variables
saifoo.khan
  • saifoo.khan
whatever you multiply with denominator.. you have to multiply the same thing with the numerator.
anonymous
  • anonymous
yeah
saifoo.khan
  • saifoo.khan
So now, u(8b^2d) = 8b^2du
anonymous
  • anonymous
so, 8b^2du - 3c^3w^3?
saifoo.khan
  • saifoo.khan
you forgot to multiply the right denominator and then the numerator.
saifoo.khan
  • saifoo.khan
you did it with left one right? now do it with right one as well.
anonymous
  • anonymous
so it would be 6c^3*d(3c^3*w^3)?
saifoo.khan
  • saifoo.khan
No. since the denominators are different. we will do something like:|dw:1339903883124:dw|
anonymous
  • anonymous
ohh okay and once i get that, the top would be 8b^2du-18c^6w^3?
saifoo.khan
  • saifoo.khan
Yes sir. that answer over \[\Large \frac{8b^2du-18c^6w^3}{48c^3 b^2 d^2}\]
anonymous
  • anonymous
okay and does that get simplified further??
saifoo.khan
  • saifoo.khan
Yes. you can take commons.
anonymous
  • anonymous
like the b^2?
saifoo.khan
  • saifoo.khan
b^2 is not in the second term.
anonymous
  • anonymous
ahh :( idk how then
saifoo.khan
  • saifoo.khan
HINT: 8 and 18
anonymous
  • anonymous
-10b^2*d*u*c^6*w^3/48c^3*b^2*d^2??
saifoo.khan
  • saifoo.khan
umm... no
anonymous
  • anonymous
:/
saifoo.khan
  • saifoo.khan
|dw:1339904363228:dw|
anonymous
  • anonymous
then theres more left to simplify or no?
saifoo.khan
  • saifoo.khan
http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG lol.
anonymous
  • anonymous
lol okay, thank you SOOOO much!!
saifoo.khan
  • saifoo.khan
No problem! (:
anonymous
  • anonymous
:) thanks again!
saifoo.khan
  • saifoo.khan
Welcome.

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