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Help is greatly appreciated

Find LCD.

dont know how to do this :/

@Tomas.A . help.

that would be great if you could help!

Ok.

\[[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]\]

|dw:1339902311825:dw|it's like that right?

yeah

So what do u think of LCD?

im not really sure, i suck at fractions :/

Right

oh okay perfect, then what??

now,
|dw:1339902810873:dw|Do you get this step?

for the most part, yeah

oh okay and for the numerator??

When we multiply that for denominator, we multiply the same thing with numerator.

how do i multiply that out though? :/

\[\Large \frac{48c^3b^2d^2}{6c^3d} \to8b^2d.\]

woah..thats the numerator?

Yes sir.

that's what u have to multiply with numerator.

i must be driving you crazy, lol, but i dont get how to multiply it and simplify afterwards..
:/

C'mon. chill up!

and tell me where are u stuck.

whatever you multiply with denominator.. you have to multiply the same thing with the numerator.

yeah

So now,
u(8b^2d) = 8b^2du

so, 8b^2du - 3c^3w^3?

you forgot to multiply the right denominator and then the numerator.

you did it with left one right? now do it with right one as well.

so it would be 6c^3*d(3c^3*w^3)?

No. since the denominators are different. we will do something like:|dw:1339903883124:dw|

ohh
okay and once i get that, the top would be 8b^2du-18c^6w^3?

Yes sir.
that answer over \[\Large \frac{8b^2du-18c^6w^3}{48c^3 b^2 d^2}\]

okay and does that get simplified further??

Yes. you can take commons.

like the b^2?

b^2 is not in the second term.

ahh :( idk how then

HINT: 8 and 18

-10b^2*d*u*c^6*w^3/48c^3*b^2*d^2??

umm... no

:/

|dw:1339904363228:dw|

then theres more left to simplify or no?

http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG
lol.

lol okay, thank you SOOOO much!!

No problem! (:

:) thanks again!

Welcome.