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Subtract. [(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)] Simplify your answer as much as possible

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Help is greatly appreciated
Find LCD.
dont know how to do this :/

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Other answers:

@Tomas.A . help.
that would be great if you could help!
\[[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]\]
|dw:1339902311825:dw|it's like that right?
So what do u think of LCD?
im not really sure, i suck at fractions :/
dont worry about fractions. it's easy. you have two things: 6c^3*d and 8b^2*d^2 open up, the numbers: 6,8 variables: c^3, d variables: b^2 d^2 agree?
So the LCD will be, 6*8 = 48 for variables, c^3 and b^2. now what about d and d^2 we always take the bigger term, so we will take d^2. Therefore our LCD will be, 48*c^3*b^2*d^2
oh okay perfect, then what??
now, |dw:1339902810873:dw|Do you get this step?
for the most part, yeah
What we have to do is, we have to make the denominators same as LCD. so we had 6c^3d.. and we have to make it as 48c^3b^2d^2 we have to multiply 6c^3d with something to make it as 48c^3b^2d^2 so we multiplied by 8b^2d.
oh okay and for the numerator??
When we multiply that for denominator, we multiply the same thing with numerator.
how do i multiply that out though? :/
\[\Large \frac{48c^3b^2d^2}{6c^3d} \to8b^2d.\]
woah..thats the numerator?
Yes sir.
that's what u have to multiply with numerator.
i must be driving you crazy, lol, but i dont get how to multiply it and simplify afterwards.. :/
C'mon. chill up!
and tell me where are u stuck.
i got the denominator, now i need to get the numerator and then simplify. i know what to multiply but i dont know how :/ i get some super long answer with a bunch of variables
whatever you multiply with denominator.. you have to multiply the same thing with the numerator.
So now, u(8b^2d) = 8b^2du
so, 8b^2du - 3c^3w^3?
you forgot to multiply the right denominator and then the numerator.
you did it with left one right? now do it with right one as well.
so it would be 6c^3*d(3c^3*w^3)?
No. since the denominators are different. we will do something like:|dw:1339903883124:dw|
ohh okay and once i get that, the top would be 8b^2du-18c^6w^3?
Yes sir. that answer over \[\Large \frac{8b^2du-18c^6w^3}{48c^3 b^2 d^2}\]
okay and does that get simplified further??
Yes. you can take commons.
like the b^2?
b^2 is not in the second term.
ahh :( idk how then
HINT: 8 and 18
umm... no
then theres more left to simplify or no? lol.
lol okay, thank you SOOOO much!!
No problem! (:
:) thanks again!

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