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jay3390 Group Title

Subtract. [(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)] Simplify your answer as much as possible

  • 2 years ago
  • 2 years ago

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  1. jay3390 Group Title
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    Help is greatly appreciated

    • 2 years ago
  2. saifoo.khan Group Title
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    Find LCD.

    • 2 years ago
  3. jay3390 Group Title
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    dont know how to do this :/

    • 2 years ago
  4. saifoo.khan Group Title
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    @Tomas.A . help.

    • 2 years ago
  5. jay3390 Group Title
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    that would be great if you could help!

    • 2 years ago
  6. saifoo.khan Group Title
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    Ok.

    • 2 years ago
  7. Tomas.A Group Title
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    \[[(u)/(6c^3*d)] - [(3c^3*w^3)/(8b^2*d^2)]\]

    • 2 years ago
  8. saifoo.khan Group Title
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    |dw:1339902311825:dw|it's like that right?

    • 2 years ago
  9. jay3390 Group Title
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    yeah

    • 2 years ago
  10. saifoo.khan Group Title
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    So what do u think of LCD?

    • 2 years ago
  11. jay3390 Group Title
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    im not really sure, i suck at fractions :/

    • 2 years ago
  12. saifoo.khan Group Title
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    dont worry about fractions. it's easy. you have two things: 6c^3*d and 8b^2*d^2 open up, the numbers: 6,8 variables: c^3, d variables: b^2 d^2 agree?

    • 2 years ago
  13. jay3390 Group Title
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    Right

    • 2 years ago
  14. saifoo.khan Group Title
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    So the LCD will be, 6*8 = 48 for variables, c^3 and b^2. now what about d and d^2 we always take the bigger term, so we will take d^2. Therefore our LCD will be, 48*c^3*b^2*d^2

    • 2 years ago
  15. jay3390 Group Title
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    oh okay perfect, then what??

    • 2 years ago
  16. saifoo.khan Group Title
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    now, |dw:1339902810873:dw|Do you get this step?

    • 2 years ago
  17. jay3390 Group Title
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    for the most part, yeah

    • 2 years ago
  18. saifoo.khan Group Title
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    What we have to do is, we have to make the denominators same as LCD. so we had 6c^3d.. and we have to make it as 48c^3b^2d^2 we have to multiply 6c^3d with something to make it as 48c^3b^2d^2 so we multiplied by 8b^2d.

    • 2 years ago
  19. jay3390 Group Title
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    oh okay and for the numerator??

    • 2 years ago
  20. saifoo.khan Group Title
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    When we multiply that for denominator, we multiply the same thing with numerator.

    • 2 years ago
  21. jay3390 Group Title
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    how do i multiply that out though? :/

    • 2 years ago
  22. saifoo.khan Group Title
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    \[\Large \frac{48c^3b^2d^2}{6c^3d} \to8b^2d.\]

    • 2 years ago
  23. jay3390 Group Title
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    woah..thats the numerator?

    • 2 years ago
  24. saifoo.khan Group Title
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    Yes sir.

    • 2 years ago
  25. saifoo.khan Group Title
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    that's what u have to multiply with numerator.

    • 2 years ago
  26. jay3390 Group Title
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    i must be driving you crazy, lol, but i dont get how to multiply it and simplify afterwards.. :/

    • 2 years ago
  27. saifoo.khan Group Title
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    C'mon. chill up!

    • 2 years ago
  28. saifoo.khan Group Title
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    and tell me where are u stuck.

    • 2 years ago
  29. jay3390 Group Title
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    i got the denominator, now i need to get the numerator and then simplify. i know what to multiply but i dont know how :/ i get some super long answer with a bunch of variables

    • 2 years ago
  30. saifoo.khan Group Title
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    whatever you multiply with denominator.. you have to multiply the same thing with the numerator.

    • 2 years ago
  31. jay3390 Group Title
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    yeah

    • 2 years ago
  32. saifoo.khan Group Title
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    So now, u(8b^2d) = 8b^2du

    • 2 years ago
  33. jay3390 Group Title
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    so, 8b^2du - 3c^3w^3?

    • 2 years ago
  34. saifoo.khan Group Title
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    you forgot to multiply the right denominator and then the numerator.

    • 2 years ago
  35. saifoo.khan Group Title
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    you did it with left one right? now do it with right one as well.

    • 2 years ago
  36. jay3390 Group Title
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    so it would be 6c^3*d(3c^3*w^3)?

    • 2 years ago
  37. saifoo.khan Group Title
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    No. since the denominators are different. we will do something like:|dw:1339903883124:dw|

    • 2 years ago
  38. jay3390 Group Title
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    ohh okay and once i get that, the top would be 8b^2du-18c^6w^3?

    • 2 years ago
  39. saifoo.khan Group Title
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    Yes sir. that answer over \[\Large \frac{8b^2du-18c^6w^3}{48c^3 b^2 d^2}\]

    • 2 years ago
  40. jay3390 Group Title
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    okay and does that get simplified further??

    • 2 years ago
  41. saifoo.khan Group Title
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    Yes. you can take commons.

    • 2 years ago
  42. jay3390 Group Title
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    like the b^2?

    • 2 years ago
  43. saifoo.khan Group Title
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    b^2 is not in the second term.

    • 2 years ago
  44. jay3390 Group Title
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    ahh :( idk how then

    • 2 years ago
  45. saifoo.khan Group Title
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    HINT: 8 and 18

    • 2 years ago
  46. jay3390 Group Title
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    -10b^2*d*u*c^6*w^3/48c^3*b^2*d^2??

    • 2 years ago
  47. saifoo.khan Group Title
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    umm... no

    • 2 years ago
  48. jay3390 Group Title
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    :/

    • 2 years ago
  49. saifoo.khan Group Title
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    |dw:1339904363228:dw|

    • 2 years ago
  50. jay3390 Group Title
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    then theres more left to simplify or no?

    • 2 years ago
  51. saifoo.khan Group Title
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    http://i0.kym-cdn.com/entries/icons/original/000/007/423/untitle.JPG lol.

    • 2 years ago
  52. jay3390 Group Title
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    lol okay, thank you SOOOO much!!

    • 2 years ago
  53. saifoo.khan Group Title
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    No problem! (:

    • 2 years ago
  54. jay3390 Group Title
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    :) thanks again!

    • 2 years ago
  55. saifoo.khan Group Title
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    Welcome.

    • 2 years ago
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