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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1339902704337:dw| FIND ACCELERATION?
D: I don't know D: @tomas.A answer it! :D
It's a her...don't be rude.

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Other answers:

Rebecca don't he so shy answer her
that's what i said ^
liezz
are'nt you members geetting mah problem on right..? do help me pleas.!!
lol um I don't know how to do this. I thought Tomas would be smart enough but I guess not ;D
i forgot all the physics when i finished it
lol someone else has arrived to help you!
it's easy........acc = net pulling force/eff mass
i know that . if you can then explain it.
see the net pullin force = 5g-2g
|dw:1339903618208:dw|
not it's 7a i guess
i get its answer 7/3 is its right
let's do it the long way.......... 5g-T=5a
T-t=(Wb)a t-2g=2a
how is it?
simultaneous equations
a = 3/10
wait wat is the wait of B? nd i dont think it's 3/10
its not given.
it's 3g/7........i guess
if T=t
Atwood machine
we hav to use only 1st and 3rd equation?
Use Newton's second law. \[\sum \vec F_i = m \vec a\]\[m_A g - m_Cg = (m_A+m_B+m_C)a\]
Agreed with @yakeyglee, And if there is friction between B and the surface on which it is kept, don't forget to subtract frictional force from the net force in your calculation.

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