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Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
dw:1339902704337:dw FIND ACCELERATION?
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
D: I don't know D: @tomas.A answer it! :D
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
It's a her...don't be rude.
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
Rebecca don't he so shy answer her
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
that's what i said ^
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
liezz
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
are'nt you members geetting mah problem on right..? do help me pleas.!!
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
lol um I don't know how to do this. I thought Tomas would be smart enough but I guess not ;D
 2 years ago

Tomas.A Group TitleBest ResponseYou've already chosen the best response.0
i forgot all the physics when i finished it
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
lol someone else has arrived to help you!
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
it's easy........acc = net pulling force/eff mass
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
i know that . if you can then explain it.
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
see the net pullin force = 5g2g
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
dw:1339903618208:dw
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
not it's 7a i guess
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
i get its answer 7/3 is its right
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
let's do it the long way.......... 5gT=5a
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
Tt=(Wb)a t2g=2a
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
simultaneous equations
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
a = 3/10
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
wait wat is the wait of B? nd i dont think it's 3/10
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
its not given.
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
it's 3g/7........i guess
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
if T=t
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
Atwood machine
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.1
we hav to use only 1st and 3rd equation?
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.1
Use Newton's second law. \[\sum \vec F_i = m \vec a\]\[m_A g  m_Cg = (m_A+m_B+m_C)a\]
 2 years ago

ujjwal Group TitleBest ResponseYou've already chosen the best response.0
Agreed with @yakeyglee, And if there is friction between B and the surface on which it is kept, don't forget to subtract frictional force from the net force in your calculation.
 2 years ago
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