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Ruchi.
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|dw:1339902704337:dw| FIND ACCELERATION?
rebeccaskell94
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D: I don't know D: @tomas.A answer it! :D
rebeccaskell94
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It's a her...don't be rude.
Tomas.A
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Rebecca don't he so shy answer her
Tomas.A
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that's what i said ^
rebeccaskell94
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liezz
Ruchi.
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are'nt you members geetting mah problem on right..? do help me pleas.!!
rebeccaskell94
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lol um I don't know how to do this. I thought Tomas would be smart enough but I guess not ;D
Tomas.A
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i forgot all the physics when i finished it
rebeccaskell94
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lol someone else has arrived to help you!
A.Avinash_Goutham
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it's easy........acc = net pulling force/eff mass
Ruchi.
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i know that .
if you can then explain it.
A.Avinash_Goutham
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see the net pullin force = 5g-2g
saifoo.khan
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|dw:1339903618208:dw|
A.Avinash_Goutham
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not it's 7a i guess
Ruchi.
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i get its answer 7/3 is its right
A.Avinash_Goutham
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let's do it the long way..........
5g-T=5a
A.Avinash_Goutham
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T-t=(Wb)a
t-2g=2a
Ruchi.
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how is it?
A.Avinash_Goutham
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simultaneous equations
saifoo.khan
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a = 3/10
A.Avinash_Goutham
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wait wat is the wait of B? nd i dont think it's 3/10
Ruchi.
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its not given.
A.Avinash_Goutham
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it's 3g/7........i guess
UnkleRhaukus
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Atwood machine
Ruchi.
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we hav to use only 1st and 3rd equation?
yakeyglee
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Use Newton's second law.
\[\sum \vec F_i = m \vec a\]\[m_A g - m_Cg = (m_A+m_B+m_C)a\]
ujjwal
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Agreed with @yakeyglee, And if there is friction between B and the surface on which it is kept, don't forget to subtract frictional force from the net force in your calculation.