anonymous
  • anonymous
question?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1339902704337:dw| FIND ACCELERATION?
anonymous
  • anonymous
D: I don't know D: @tomas.A answer it! :D
anonymous
  • anonymous
It's a her...don't be rude.

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anonymous
  • anonymous
Rebecca don't he so shy answer her
anonymous
  • anonymous
that's what i said ^
anonymous
  • anonymous
liezz
anonymous
  • anonymous
are'nt you members geetting mah problem on right..? do help me pleas.!!
anonymous
  • anonymous
lol um I don't know how to do this. I thought Tomas would be smart enough but I guess not ;D
anonymous
  • anonymous
i forgot all the physics when i finished it
anonymous
  • anonymous
lol someone else has arrived to help you!
anonymous
  • anonymous
it's easy........acc = net pulling force/eff mass
anonymous
  • anonymous
i know that . if you can then explain it.
anonymous
  • anonymous
see the net pullin force = 5g-2g
saifoo.khan
  • saifoo.khan
|dw:1339903618208:dw|
anonymous
  • anonymous
not it's 7a i guess
anonymous
  • anonymous
i get its answer 7/3 is its right
anonymous
  • anonymous
let's do it the long way.......... 5g-T=5a
anonymous
  • anonymous
T-t=(Wb)a t-2g=2a
anonymous
  • anonymous
how is it?
anonymous
  • anonymous
simultaneous equations
saifoo.khan
  • saifoo.khan
a = 3/10
anonymous
  • anonymous
wait wat is the wait of B? nd i dont think it's 3/10
anonymous
  • anonymous
its not given.
anonymous
  • anonymous
it's 3g/7........i guess
anonymous
  • anonymous
if T=t
UnkleRhaukus
  • UnkleRhaukus
Atwood machine
anonymous
  • anonymous
we hav to use only 1st and 3rd equation?
anonymous
  • anonymous
Use Newton's second law. \[\sum \vec F_i = m \vec a\]\[m_A g - m_Cg = (m_A+m_B+m_C)a\]
ujjwal
  • ujjwal
Agreed with @yakeyglee, And if there is friction between B and the surface on which it is kept, don't forget to subtract frictional force from the net force in your calculation.

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