kaiz122
  • kaiz122
integrate(cos^3 x)/sin(x) dx
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

kaiz122
  • kaiz122
|dw:1339945551113:dw|
anonymous
  • anonymous
bhyu
kaiz122
  • kaiz122
what?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Let u = cos x du = -sin x dx then, "integral [u^3 -du]" or "- integral [u^3 du] " = -(u^4)/4 + C = -(cos^4 x)/4 + C
kaiz122
  • kaiz122
i have a question, sin x is in the denominator, how does it become the du then?
anonymous
  • anonymous
Because everything is substituted and then flipped :)
kaiz122
  • kaiz122
i tried checking it by differentiation, then i got (cos^3x )(-sinx)
anonymous
  • anonymous
Are you using your calculator?
kaiz122
  • kaiz122
no,
anonymous
  • anonymous
You can integrate this directly, just notice that differentiating cos^4(x) gives you -4cos^3(x)sin(x) by the chain rule. Hence the integral of cos^3(x)sin(x) is -1/4 cos^4(x)
kaiz122
  • kaiz122
i still don't get it, how does sin x in the denominator becomes du? dx/sinx is not equal to sinx dx right.
anonymous
  • anonymous
No their not the equal
kaiz122
  • kaiz122
@saifoo.khan can you please help me here
saifoo.khan
  • saifoo.khan
@dpaInc HELP!!!!!
anonymous
  • anonymous
|dw:1339951134590:dw|
kaiz122
  • kaiz122
thank you
AravindG
  • AravindG
oh i was late :(
AravindG
  • AravindG
use @AravindG if u have any integration qns in future

Looking for something else?

Not the answer you are looking for? Search for more explanations.