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integrate(cos^3 x)/sin(x) dx

Mathematics
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bhyu
what?

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Other answers:

Let u = cos x du = -sin x dx then, "integral [u^3 -du]" or "- integral [u^3 du] " = -(u^4)/4 + C = -(cos^4 x)/4 + C
i have a question, sin x is in the denominator, how does it become the du then?
Because everything is substituted and then flipped :)
i tried checking it by differentiation, then i got (cos^3x )(-sinx)
Are you using your calculator?
no,
You can integrate this directly, just notice that differentiating cos^4(x) gives you -4cos^3(x)sin(x) by the chain rule. Hence the integral of cos^3(x)sin(x) is -1/4 cos^4(x)
i still don't get it, how does sin x in the denominator becomes du? dx/sinx is not equal to sinx dx right.
No their not the equal
@saifoo.khan can you please help me here
@dpaInc HELP!!!!!
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thank you
oh i was late :(
use @AravindG if u have any integration qns in future

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