Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

How do you factor this? (Algebra 3)

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

\[16x ^{3}-64x ^{2}\]
hint: common factor will be 16 and x^2
I did that, but there are more steps to just that isn't there?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

thats all there is - why don't you write out what you got and we can check if its correct?
think of there GCF, which is 16x2 then think about how you will get 64x^2 SO what do 16x^3 and 64x^2 have in common? x and 4 right!! so the you basically you get \[16x^2(x-4)\] Then you can check to see if thats right by using the distributive property!!
That's it? My teacher taught us to bracket our answers, and it just really confused me.
yea basically....if you have more problems you can just visit

Not the answer you are looking for?

Search for more explanations.

Ask your own question