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A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?
 one year ago
 one year ago
A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?
 one year ago
 one year ago

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FoolForMathBest ResponseYou've already chosen the best response.2
Let the length of the equal sides be \(x\) inches then: \(2x + x2 = 43 \implies 3x = 45 \implies x = 15 \) inches
 one year ago

radarBest ResponseYou've already chosen the best response.1
We know that the sum of the three sides (the perimeter) is 43 inches. Let x = lenght of one of the equal sides then the base is x2 inches (given) lets add up the three sides x2 + x + x which is 3x2 and equal to 43 3x2 = 43 3x=45 x=15 in. the equal sides are 15, and the base is 152 or 13 inches.
 one year ago

tbrooks3Best ResponseYou've already chosen the best response.0
okay i figured u would do it like that but i wasnt sure thanks u 2.
 one year ago
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