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tbrooks3
 2 years ago
A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?
tbrooks3
 2 years ago
A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?

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FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.2Let the length of the equal sides be \(x\) inches then: \(2x + x2 = 43 \implies 3x = 45 \implies x = 15 \) inches

radar
 2 years ago
Best ResponseYou've already chosen the best response.1We know that the sum of the three sides (the perimeter) is 43 inches. Let x = lenght of one of the equal sides then the base is x2 inches (given) lets add up the three sides x2 + x + x which is 3x2 and equal to 43 3x2 = 43 3x=45 x=15 in. the equal sides are 15, and the base is 152 or 13 inches.

tbrooks3
 2 years ago
Best ResponseYou've already chosen the best response.0okay i figured u would do it like that but i wasnt sure thanks u 2.
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