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tbrooks3

  • 3 years ago

A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?

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  1. FoolForMath
    • 3 years ago
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    Let the length of the equal sides be \(x\) inches then: \(2x + x-2 = 43 \implies 3x = 45 \implies x = 15 \) inches

  2. radar
    • 3 years ago
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    We know that the sum of the three sides (the perimeter) is 43 inches. Let x = lenght of one of the equal sides then the base is x-2 inches (given) lets add up the three sides x-2 + x + x which is 3x-2 and equal to 43 3x-2 = 43 3x=45 x=15 in. the equal sides are 15, and the base is 15-2 or 13 inches.

  3. tbrooks3
    • 3 years ago
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    okay i figured u would do it like that but i wasnt sure thanks u 2.

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