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tbrooks3
A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?
Let the length of the equal sides be \(x\) inches then: \(2x + x-2 = 43 \implies 3x = 45 \implies x = 15 \) inches
We know that the sum of the three sides (the perimeter) is 43 inches. Let x = lenght of one of the equal sides then the base is x-2 inches (given) lets add up the three sides x-2 + x + x which is 3x-2 and equal to 43 3x-2 = 43 3x=45 x=15 in. the equal sides are 15, and the base is 15-2 or 13 inches.
okay i figured u would do it like that but i wasnt sure thanks u 2.