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lgbasallote

  • 2 years ago

PLEASE HELP!!! IT'S 3 AM HERE AND I NEED THIS HOMEWORK EXPLAINED!!! OpenStudy user s.k has 343 fans less than a64. If s.k gets 3 fans a week while a64 gets 2 fans a week, how long will it take s.k to get twice the fans a64 has?

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  1. saifoo.khan
    • 2 years ago
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    LOL. nice thought.

  2. saifoo.khan
    • 2 years ago
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    s.k. fans = x a64 fans = y y = 343 + x i get till here..

  3. lgbasallote
    • 2 years ago
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    im thinking y + 2a = x + 3a?

  4. Akshay_Budhkar
    • 2 years ago
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    After z weeks the number of fans of s.k= x+3z and a64= y+2z

  5. lgbasallote
    • 2 years ago
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    no wait..that's for them to equal..

  6. lgbasallote
    • 2 years ago
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    if s.k. will double then 2(y + 2z) = x + 3z?

  7. Akshay_Budhkar
    • 2 years ago
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    now we want them to be twice, so we want x+3z=2(y+2z)

  8. ganeshie8
    • 2 years ago
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    y1 = 3/7 x y2 = 2/7 x + 343

  9. lgbasallote
    • 2 years ago
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    x + 3z = 2y + 4z x - 2y = z what does that mean?

  10. lgbasallote
    • 2 years ago
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    x - 2(343 + x)?

  11. ganeshie8
    • 2 years ago
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    y1 = 3/7 x y2 = 2/7 x + 343 y1 = 2y2 solve for x

  12. lgbasallote
    • 2 years ago
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    how did you get those @ganeshie8 ?

  13. ganeshie8
    • 2 years ago
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    y1: number of fans of sk y2 : number of fans of a64 y1 is increasing his fans at a rate of 3 per 7 days right so slope of y1 is 3/7 put y1 equation in slope intercept form

  14. Akshay_Budhkar
    • 2 years ago
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    yea agreed^ why did i introduce a new variable O_O?

  15. saifoo.khan
    • 2 years ago
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    lol ^

  16. ganeshie8
    • 2 years ago
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    to start with, a64 has 343 as y intercept.. hope you get the idea..

  17. lgbasallote
    • 2 years ago
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    3/7 x = 2(2/7x +343) 3/7 x - 4/7 x = 868 -1/7 x = 868??? this seems weird

  18. lgbasallote
    • 2 years ago
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    uhm it's 686 lol

  19. lgbasallote
    • 2 years ago
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    but still negative so weird o.O

  20. saifoo.khan
    • 2 years ago
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    So sk should start asking people to unfan him? :O

  21. lgbasallote
    • 2 years ago
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    lol =)))))

  22. saifoo.khan
    • 2 years ago
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    Sounds like a plan. NOT.

  23. lgbasallote
    • 2 years ago
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    s.k should put up a teenage asian girl...

  24. lgbasallote
    • 2 years ago
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    pic

  25. saifoo.khan
    • 2 years ago
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    Ok, this sounds like a better plan. :D

  26. saifoo.khan
    • 2 years ago
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    what is this guy typing from a hour?

  27. lgbasallote
    • 2 years ago
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    even with values im getting negative lol

  28. ganeshie8
    • 2 years ago
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    me.. ? im not typing anythign... just watching hindi movie i thoutht lgba got the answer... ?

  29. saifoo.khan
    • 2 years ago
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    No, i was talking about lgba.

  30. lgbasallote
    • 2 years ago
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    no i didnt get the answer..im getting negatives

  31. lgbasallote
    • 2 years ago
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    the time when they equal is just easy...could it be that it's impossible for s.k to get double the fans of a64?? o.O

  32. saifoo.khan
    • 2 years ago
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    Possibility..

  33. ganeshie8
    • 2 years ago
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    yeah that can happen in reality... but equations.. we should get +ve numb er of days

  34. lgbasallote
    • 2 years ago
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    let's try solving for equal first... x + 3z = y + 2z z = y - x <---this is the time when they become equal

  35. lgbasallote
    • 2 years ago
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    assuming they are already equal let a be their values a + 3n = 2(a + 2n) a + 3n = 2a + 4n a - 2a = n <---the time when they double

  36. lgbasallote
    • 2 years ago
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    so if z + n = -a + a = 0??? o.O

  37. saifoo.khan
    • 2 years ago
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    LOL.

  38. Akshay_Budhkar
    • 2 years ago
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    equal? u want it twice..

  39. lgbasallote
    • 2 years ago
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    wth am i doing wrong =_=

  40. lgbasallote
    • 2 years ago
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    well it didnt work lol..i just tried

  41. lgbasallote
    • 2 years ago
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    why am i getting negative @Akshay_Budhkar ? any ideas>

  42. Akshay_Budhkar
    • 2 years ago
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    i am working on it gimme a moment

  43. lgbasallote
    • 2 years ago
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    ugh i gtg...will be back in an hour... if any one of you got some ideas pls feel free to post it here

  44. ganeshie8
    • 2 years ago
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    ok me too confused..

  45. lgbasallote
    • 2 years ago
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    i dont think i did anything wrong in the solution :/

  46. Akshay_Budhkar
    • 2 years ago
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    are we missing an equation??

  47. Akshay_Budhkar
    • 2 years ago
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    yea we need another equation, the answer will depend on the initial values of a and b!! try taking two diff sets of the numbers and solving

  48. Akshay_Budhkar
    • 2 years ago
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    @saifoo.khan ^

  49. abstracted
    • 2 years ago
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    I don't think you can solve this until you have another equation. We have 3 variables (a= s.k fans, b=a64 fans, and w=weeks) but only two equations, so it is unsolvable. right?

  50. lgbasallote
    • 2 years ago
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    well x and y dont really matter. as long as you get a numerical value...but let's say s.k has 914 fans and a64 was 1257..it still becomes negative

  51. lgbasallote
    • 2 years ago
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    @ganeshie8 still nothing? even if there are values?

  52. ganeshie8
    • 2 years ago
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    343 + 3t = 2{ 2t} => t = 343 weeks in 343 weeks sk fans will become twice that of a64. i am still lost in straight lines.. i want to see you or someone else explain the answer @lgbasallote @shubhamsrg @abstracted @Akshay_Budhkar

  53. ganeshie8
    • 2 years ago
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    @mathslover

  54. lgbasallote
    • 2 years ago
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    how did you get 343 again?

  55. blockcolder
    • 2 years ago
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    You can just say that every week, s.k's lead will be reduced by one so that after 343 weeks, s.k's lead will be zero.

  56. lgbasallote
    • 2 years ago
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    wait what?

  57. Akshay_Budhkar
    • 2 years ago
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    @ganeshie8 the straight line stuff wont work, the intercept is wrong, you dont know the intercept. @lgba the question is incomplete...

  58. saifoo.khan
    • 2 years ago
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    @lgbasallote , come up with the complete question next time! -_- i want to find a way out.

  59. ganeshie8
    • 2 years ago
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    @Akshay_Budhkar ,straight line logic may not tell the answer straight away.. but it works. @saifoo.khan , the question @lgbasallote posted is complete. answer is : sk can never achieve his goal. because with a 3t rate he can never reach 2(2t) value !! 3t < 2 (2t + 343) 3t < 4t + ....

  60. Akshay_Budhkar
    • 2 years ago
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    @ganeshie8 it is pretty illogical... he can achieve his goal!! He is going at a faster rate man

  61. Akshay_Budhkar
    • 2 years ago
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    lol take real life example of 0 fans and 343 fans and solve, it works

  62. ganeshie8
    • 2 years ago
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    for positive values of t, 3t <= 2(2t + 300 ) u agree... ?

  63. ganeshie8
    • 2 years ago
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    @Akshay_Budhkar

  64. lgbasallote
    • 2 years ago
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    but how could it not be possible?? o.O i mean soon s.k is gonna overtake a64 then after that s.k will always be leading there should be a time when s.k will get twice :O

  65. lgbasallote
    • 2 years ago
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    let's say both of them start at 0... 1st week - s.k is 3... a64 is 2 2nd week - 6 - 4 3rd week - 9 - 6 4th week - 12 - 8 5th week - 15 - 10 6th week - 18 -12 see how s.k's lead is gettingbigger...that should double sometime

  66. Limitless
    • 2 years ago
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    Let \(x\) be a64's number of fans. Let \(y\) be s.k.'s number of fans. We have \(y(x; w=0)=x_i-343.\) which is the initial value for \(y\) based on the initial value of \(x.\) Based on how they gain fans, we have: \(y(x,w)=x_i-343+3w.\) We want to find the point at which \(y(x,w)=2x(w)\). Note that \(x(w)=x_i+2w.\) Thus we have, \(x_i-343+3w=2x_i+4w.\) Let's let \(x_i\) be a constant. So, we have: \(-x_i-343=w\) We assume that \(x_i \in \mathbb{Z}^+.\) This tells us that \(y(x,w)\) will never have twice as many fans as \(x(w)\) if the functions behave as they have been defined. It actually says that we would have to go "backward" to reach a point where \(y(x,w)\) had twice as many fans as \(x(w)\). Also, you contradicted yourself, lgba: "let's say both of them start at 0..." This contradicts the premise that they would start in relation to one another. (i.e. \(y(x;w=0)=x_i-343\) and \(x(w)=x_i+2w.\)) Now let's suppose this: Both \(x\) and \(y\) start at some value \(x_0\) and \(y_0\) respectively. Their growth functions are \(x(w)=x_0+2w\) and \(y(w)=y_0+3w.\) If we want to find the point at which \(y(w)=2x(w),\) we have \(y_0+3w=2x_0+4w\) which is \(w=y_0-2x_0.\) You can see how this makes no sense in your original presumptions. We can continue this logic further and deduce that this problem makes no sense if \(x_0 > \frac{y_0}{2}.\) What I find most interesting is that while there is no point in future time that \(y(w)=2x(w),\) there is a point where \(y(w)=x(w).\) This happens to be \(w=x_0-y_0.\) It is this fact that makes one speculate that there is a point where \(y(w)=2x(w)\), but there is no such point in future time.

  67. Limitless
    • 2 years ago
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    Oh, cool! I also figured out something else: \[ \begin{align} f(x)&=m_fx+b_f\\ g(x)&=m_gx+b_g\\ \lim_{x \to \infty }\frac{f(x)}{g(x)}&=\frac{m_f}{m_g} \end{align} \] This explains everything.

  68. Limitless
    • 2 years ago
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    (Note: that infinity should be \(+\infty.\))

  69. ganeshie8
    • 2 years ago
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    @lgbasallote let's say both of them start at 0... 1st week - s.k is 3... a64 is 2 2nd week - 6 - 4 3rd week - 9 - 6 4th week - 12 - 8 5th week - 15 - 10 6th week - 18 -12 . . . 100th week - 300 - 200 1000th week - 3000 - 2000 10000th week - 30000 - 20000 lol both must have died by now... the trick is "a 3t rate can never increase its value to 2(2t)"

  70. Limitless
    • 2 years ago
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    @ganeshie8, I just said that. You essentially copied my work.

  71. ganeshie8
    • 2 years ago
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    lol.. i copied your work :)

  72. lgbasallote
    • 2 years ago
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    but...but... T_T sorry @saifoo.khan seems amistre is unbeatable

  73. lgbasallote
    • 2 years ago
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    but...but... T_T sorry @saifoo.khan seems amistre is unbeatable

  74. Limitless
    • 2 years ago
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    @lgbasallote, you can get above amistre. You simply cannot get to where you are double him.

  75. lgbasallote
    • 2 years ago
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    yeah...what i meant lol

  76. saifoo.khan
    • 2 years ago
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    @lgbasallote = Good for nothing!!! =__= Jk

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