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inkyvoyd
Group Title
Integrate
\(\frac{\frac{1}{\sqrt{2}v}}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1}\)
 2 years ago
 2 years ago
inkyvoyd Group Title
Integrate \(\frac{\frac{1}{\sqrt{2}v}}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1}\)
 2 years ago
 2 years ago

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inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@nbouscal will know what I am talking about, or maybe @Limitless
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Wait, correction.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
\(\frac{\frac{1}{\sqrt{2}}v}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1}\)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Am I supposed to complete the square?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@dpaInc , pwease help me!
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
can't see it so i'm gonna copy it... and make it huge... \[\huge \frac{\frac{1}{\sqrt{2}}v}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1} \]
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@dpaInc , how do you copy it like that?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
right click>show math as>tex commands
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \int\frac{\frac{1}{\sqrt{2}}v}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1}dv \]
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Alright, now solve NAO!
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
btw, this is the equation I got after trying 3 substitutions and seperating the fraction.
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
\[\large \int\frac{\frac{1}{\sqrt{2}}v}{v^2+\sqrt{2}v+1}+\frac{\frac{1}{\sqrt{2}}v}{v^2\sqrt{2}v+1}dv\] \[\large \frac{1}{\sqrt2}\int\frac{v}{v^2+\sqrt{2}v+1}dv+\frac{1}{\sqrt2}\int \frac{v}{v^2\sqrt{2}v+1}dv\] maybe i should just draw...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@dpaInc , now do I complete the square?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
yeah... that's what i was about to do... but i think there is a formula... hang on....
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
there it is.... #13....:) http://integraltable.com/downloads/singlepageintegraltable.pdf
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
i mean #16...l
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
\(\huge \frac{1}{\sqrt2}\int\frac{v}{(v+\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv+\frac{1}{\sqrt2}\int \frac{v}{(v\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv\)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
But isn't using tables cheating?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
no... of course not...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
But... I don't know where the tables come from... >.<
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
it's like using all the different tires for your car... you're not going to make/invent your own tires are you? oh wait.. do you drive yet?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
No lol. I'M GOING TO BUILD MY CAR FROM SCRATCH MUAHAHAHA
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
i don't think it's cheating... it's a good shortcut to cut through all that stuff..
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Okay... @dpaInc , without showing me the math, can you tell me what to do after I have completed the square?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
and as for me, i haven't really started using the integral tables until i saw everyon virtually used them here on OS.... i actually went through proving stuff because I don't use/memorize the tables...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@dpaInc , my problem is that I'm not sure how to get the results shown in the tables.
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
let me complete the square on the first integral... i haven't done it for a while and i guess i need the practice...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
I already did in my last tex post :)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
\huge \frac{1}{\sqrt2}\int\frac{v}{(v+\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv+\frac{1}{\sqrt2}\int \frac{v}{(v\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
oh... i see you did it already....
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
you are solving the problem in a wrong way
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@nitz , what am I doing wrong?
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
see firstly make numerator as the derivative of denominator
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Can you show me?
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
i am talking about 1st integration ie before addition
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
in it, firstly multiply the numerator with 2 and add and subtract \[\sqrt{ 2} \] in it
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
You mean at the very start of the problem?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
but but but
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
\(\huge \frac{1}{\sqrt2}\int\frac{v}{(v+\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv+\frac{1}{\sqrt2}\int \frac{v}{(v\frac{\sqrt{2}}{2})^2+\frac{1}{2}}dv\) we already got to here >.<
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
you cant solve it further in this case
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
#16? http://integraltable.com/downloads/singlepageintegraltable.pdf
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
these are direct problems
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
these are direct solutions
 2 years ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
you can apply direct formula
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
i think it works.... dw:1340004704215:dw
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Uh, I can't use u in substiution LOL. I already used it...
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.1
Okay, I'm late to this party, but you can just complete the square and then do a substitution. This is just like the case that we reach in the integration of sqrt(tan x) that we have already done, inky.
 2 years ago

Limitless Group TitleBest ResponseYou've already chosen the best response.0
Next OS question: What made this integral appealing? I will medal the person with the best response.
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.1
This actually looks very similar to the integral of sqrt(tan x), if I had to guess I would say it is an intermediate step in a similar integration.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
@nbouscal , that was my integration of the square root of tan x...
 2 years ago

Limitless Group TitleBest ResponseYou've already chosen the best response.0
nbouscal: Integral Detective
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Maybe I should show what work i did before...
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.1
I didn't actually go back and look at that integral, you're probably right on. The next step is indeed to complete the square, then do another substitution.
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.1
Oh hey just look here: http://openstudy.com/study#/updates/4fb3c611e4b0556534298c6b
 2 years ago
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