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waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Linear by Quadratic...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
But, how exactly am I supposed to do this one?
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
If you put ax2 + bx + c = y then it helps or not??
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
uhh... what about the top  we just substitute using the quadratic formula in that case?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Sorry guys, I'm not even sure where to start with this integral. I can't find it in my book either >.<
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
bring everything on the bottom to the top... then integration by parts?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
uhh  I'm not sure that will work >.<
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
why not...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
All the related integrals had something to do with trig sub and inverse trig functions, but i can't find this case.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
I know what the answer is (from an integral table), and it's logarithmic+trigonometric. I have no idea where to start though
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
http://integraltable.com/downloads/singlepageintegraltable.pdf #16, btw
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
ahhh that got me thinkin... let me take another look
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
well log came from 1/x
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
that looks like a big u sub
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Uh, got any ideas where to start htough?
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
just by the looks w/o really thinking about it, it looks like they let the bottom = u
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
then factor out a 2a
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
lol nvm i thought the second half was the next step
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
thats a tricky one i need a piece of paper for that one lol
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
okay lol. Thanks for helping :P
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=int+x%2F+%28ax2+%2B+bx+%2B+c%29
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
that way is crazzyyyy tho lol
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
lol  but the answer is different from the integral table :S the result is too complicated lol. I'm using some constants for the integral that will make it even more nasty x.x
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
its the same just written different
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
x = 1/2(2x + b/a)  1/2 (b/a) make two fractions ... and use the usual approach
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
^^^ thats what w.a did too
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Okay. any way to reduce it to the form seen in the integral table?
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
probably not
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
once i substitute my values in, it is still an intermediate result  I still have to do two more substitutions, and I'm not sure I can do the algebra without going insane.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
one is going to be log another ... complete squares (a+sqrt(b/4a))^2  (b/4ac)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
this is in standard form ... you should be able to evaluate this.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Wait, I can do it by completing the square as well?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
\[ \frac1{2a}\frac{x + b/a}{x + b/a x+c/a}  \frac1{2a}\frac{ b/a}{(x + \sqrt{b/4a})^2  (b/4ac/a)}\]
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
oh wow. this integral  sqrt(tan x)  is a freaking pain...
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
quite a bit ... assuming c/a > b/4a
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
yea just about all realistic functions are either extremely tedious or impossible to solve by hand. When it comes to practical application, we usually just have computers solve or approximate the solution.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Ugh, I give up. I'm tired of this integral lol. I'll look into it more tomorrow. Thanks though, @experimentX and @eyust707
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
thats when the mathematicians come in handy =P
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
yw inky.. you taking calc 2 over the summer??
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
I'm trying to finish calc 3 and linear algebra and diff equations over the summer >.<
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
that is a lot of material to learn!!
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Yea, hopefully I can finish it.
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
I got faith!! where about are you in diffs?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Haven't even started LOL
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
haha I see I see
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
well, I skimmed the variables seperatble and the first order linear ODE I think
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
It's just a substitution ... reduces to the form \[ \int \frac1 {x^2 + a^2}dx\] or, \[ \int \frac 1{x^2  a^2}dx\] assuming first, wolf calculates 2/a arctan(x/a)
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
yea seps will seem very natural
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
linear first order with the integrating factor is tricky to understand at first... but easy to do
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
youll prob see frustrating word problems but dont let them scare you.. they always work out to be quite simple
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
alright  I have to learn how to integrate these nasty partial fractions first though haha :P
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
haha just remember, If your integrating with respect to y , all the other variables are constant!
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
keep repeating that in your head as you run through your derivative..
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.1
pretend that all the other letters are just numbers and youll be golden!
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
didn't you see what i last posted earlier inky?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
uhh what did you post?
 2 years ago
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