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RandiHobbs

A circle with a right triangle with 16.2 next to it and then on the hypotenuse 24.6 I will draw out the picture when someone replies.

  • one year ago
  • one year ago

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  1. King
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    can u post the picture nw?

    • one year ago
  2. King
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    @RandiHobbs

    • one year ago
  3. King
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    POST the picture pls

    • one year ago
  4. RandiHobbs
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    |dw:1340022316767:dw|

    • one year ago
  5. RandiHobbs
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    What is the area of the sector AEB when AE= 8yd?

    • one year ago
  6. King
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    |dw:1340022466528:dw|

    • one year ago
  7. King
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    is that rite?

    • one year ago
  8. RandiHobbs
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    a.)8pi yd^2 b.)2pi yd^2 c.)4pi yd^2 d.)16pi yd^2

    • one year ago
  9. RandiHobbs
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    Yes, that's right.

    • one year ago
  10. King
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    nw see here area of a sector is theta/360 times pi r^2 theta is 90 so theta/360=1/4 1/4 * pi * 8* 8 16pi yd^2...........

    • one year ago
  11. King
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    understood?

    • one year ago
  12. RandiHobbs
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    16pi yd^2? I understand, thankyou.

    • one year ago
  13. King
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    ure welcome!!

    • one year ago
  14. RandiHobbs
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    Perhaps you could attempt another one for me?

    • one year ago
  15. King
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    pls close the question...and yeah why not....

    • one year ago
  16. King
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    post it separately.........

    • one year ago
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