anonymous
  • anonymous
A circle with a right triangle with 16.2 next to it and then on the hypotenuse 24.6 I will draw out the picture when someone replies.
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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King
  • King
can u post the picture nw?
King
  • King
King
  • King
POST the picture pls

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anonymous
  • anonymous
|dw:1340022316767:dw|
anonymous
  • anonymous
What is the area of the sector AEB when AE= 8yd?
King
  • King
|dw:1340022466528:dw|
King
  • King
is that rite?
anonymous
  • anonymous
a.)8pi yd^2 b.)2pi yd^2 c.)4pi yd^2 d.)16pi yd^2
anonymous
  • anonymous
Yes, that's right.
King
  • King
nw see here area of a sector is theta/360 times pi r^2 theta is 90 so theta/360=1/4 1/4 * pi * 8* 8 16pi yd^2...........
King
  • King
understood?
anonymous
  • anonymous
16pi yd^2? I understand, thankyou.
King
  • King
ure welcome!!
anonymous
  • anonymous
Perhaps you could attempt another one for me?
King
  • King
pls close the question...and yeah why not....
King
  • King
post it separately.........

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