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RandiHobbs

  • 3 years ago

A circle with a right triangle with 16.2 next to it and then on the hypotenuse 24.6 I will draw out the picture when someone replies.

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  1. King
    • 3 years ago
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    can u post the picture nw?

  2. King
    • 3 years ago
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    @RandiHobbs

  3. King
    • 3 years ago
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    POST the picture pls

  4. RandiHobbs
    • 3 years ago
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    |dw:1340022316767:dw|

  5. RandiHobbs
    • 3 years ago
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    What is the area of the sector AEB when AE= 8yd?

  6. King
    • 3 years ago
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    |dw:1340022466528:dw|

  7. King
    • 3 years ago
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    is that rite?

  8. RandiHobbs
    • 3 years ago
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    a.)8pi yd^2 b.)2pi yd^2 c.)4pi yd^2 d.)16pi yd^2

  9. RandiHobbs
    • 3 years ago
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    Yes, that's right.

  10. King
    • 3 years ago
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    nw see here area of a sector is theta/360 times pi r^2 theta is 90 so theta/360=1/4 1/4 * pi * 8* 8 16pi yd^2...........

  11. King
    • 3 years ago
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    understood?

  12. RandiHobbs
    • 3 years ago
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    16pi yd^2? I understand, thankyou.

  13. King
    • 3 years ago
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    ure welcome!!

  14. RandiHobbs
    • 3 years ago
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    Perhaps you could attempt another one for me?

  15. King
    • 3 years ago
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    pls close the question...and yeah why not....

  16. King
    • 3 years ago
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    post it separately.........

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