Here's the question you clicked on:
FoolForMath
Just another very easy problem: In an exam, \(5%\) applicants were ineligible and \(85%\) of eligible belonged to A category. If \(4275\) eligible belong to other categories, how many applied? If you google you will be spoiling your fun :)
Apparently that is not the correct answer.
dont laugh but i think its 4,365
i got it now we'll suppose no of total applicants = x 95% of which are eligible 5% are ineligible so,
95/100 * x is the eligible category
85/100 * x are category A and eligible 100-85 = 15 so 15/100*x are other category and eligible so, 15% of (95% of x) so 15/100 * 95/100* x 0.1425x but the question tells us that other category guyz are 4275 so 0.1425x = 4275 x= 4275/0.1425 x = 30,000 @FoolForMath i solved it :)
I got the same answer. But to some weird reason the answer is 35,000. You may Google now :)
http://caribflyer.com/carib/wp-content/uploads/thumbs-up.png
@FoolForMath then i was correct u told i was wrong hm.......!!