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careless850
 3 years ago
Simplify!
careless850
 3 years ago
Simplify!

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careless850
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac {12x^{5}}{20x^{2}}\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.0can you simplify just the numbers? the 12/20 part?

cornitodisc
 3 years ago
Best ResponseYou've already chosen the best response.0divide them by 4..3/5 is the answer..

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0I want to know how to do this.

phi
 3 years ago
Best ResponseYou've already chosen the best response.0can you find the factors of 12? like 3*4 for example for 20, 4*5 so the numbers part is \[ \frac{3\cdot 4}{4\cdot 5} \] the 4's "cancel" (that means 4/4 =1) you get 3/5

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0but the thing is. how would i know how to do that?

phi
 3 years ago
Best ResponseYou've already chosen the best response.0the x's are actually not too hard, if you remember this rule: if dividing x's to different powers, subtract the powers.

cornitodisc
 3 years ago
Best ResponseYou've already chosen the best response.0\[(12/20) \div4=3/5\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.0but the thing is. how would i know how to do that? for 12/20 notice that both are even. so you divide both by 2. 6/10 they are still even, divide by 2 again 3/5

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0but what aout the powers?

phi
 3 years ago
Best ResponseYou've already chosen the best response.0there a simple tricks to know if a number is divisible by another: a number is even 2 sum of digits divisible by 3 then the number is divisible by 3 both of the above, then divisible by 6 ends in 0 or 5, divisible by 5

phi
 3 years ago
Best ResponseYou've already chosen the best response.0powers are easier. subtract when dividing. add when multiplying here is how to remember: x^2 means x*x x^3 means x*x*x multiply: x^2 * x^3 = x*x * x*x*x count the x's It is x^5 (the sum of 2 and 3)

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0So, on my problem, we'd subtract?

phi
 3 years ago
Best ResponseYou've already chosen the best response.0for \[ \frac{x^5}{x^2} = \frac{x*x*x*x*x}{x*x}\] we can cancel 2 of the x's from the top and bottom to get \[ \frac{x^5}{x^2} = \frac{x*x*x*\cancel{x}*\cancel{x}}{\cancel{x}*\cancel{x}}= x*x*x \] and x*x*x is written as \(x^3 \) because people don't like writing out all those x's

phi
 3 years ago
Best ResponseYou've already chosen the best response.0notice that the rule is just a fast way to get to the answer 52= 3

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0so my answer would ACTUALLY be \[\frac {3}{5}x^{3}\]

careless850
 3 years ago
Best ResponseYou've already chosen the best response.0Could you help with another?
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