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\[\cos^2x-\sin^2x =sinx\]

I see trig... I see trig stuff squared... im thinkin trig identities right off the bat!

cox 2x comes to mind...

but it's useless, I think?

no i like the thinking!

LOL, this is a quadratic equation in disguise

cos^2 x = 1 - sin^2 x right?
so we can turn it into...
1 - sin^2 x - sin^2 x = sin x

\[\cos^2x-\sin^2=1-2\sin^2x\]

oops :P
ditto

Oh, you can do it from here? great :)

I'm not the asker
@ksaimouli can you take it from here?

derp, I forgot about that (sorry)