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ksaimouli

  • 2 years ago

solve for x cos^2x-sin^2x=sin x

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  1. ksaimouli
    • 2 years ago
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    \[\cos^2x-\sin^2x =sinx\]

  2. eyust707
    • 2 years ago
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    I see trig... I see trig stuff squared... im thinkin trig identities right off the bat!

  3. terenzreignz
    • 2 years ago
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    cox 2x comes to mind...

  4. terenzreignz
    • 2 years ago
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    but it's useless, I think?

  5. eyust707
    • 2 years ago
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    no i like the thinking!

  6. terenzreignz
    • 2 years ago
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    LOL, this is a quadratic equation in disguise

  7. terenzreignz
    • 2 years ago
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    cos^2 x = 1 - sin^2 x right? so we can turn it into... 1 - sin^2 x - sin^2 x = sin x

  8. colorful
    • 2 years ago
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    \[\cos^2x-\sin^2=1-2\sin^2x\]

  9. colorful
    • 2 years ago
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    oops :P ditto

  10. terenzreignz
    • 2 years ago
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    Oh, you can do it from here? great :)

  11. colorful
    • 2 years ago
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    I'm not the asker @ksaimouli can you take it from here?

  12. terenzreignz
    • 2 years ago
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    derp, I forgot about that (sorry)

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