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ksaimouli

solve for x cos^2x-sin^2x=sin x

  • one year ago
  • one year ago

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  1. ksaimouli
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    \[\cos^2x-\sin^2x =sinx\]

    • one year ago
  2. eyust707
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    I see trig... I see trig stuff squared... im thinkin trig identities right off the bat!

    • one year ago
  3. terenzreignz
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    cox 2x comes to mind...

    • one year ago
  4. terenzreignz
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    but it's useless, I think?

    • one year ago
  5. eyust707
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    no i like the thinking!

    • one year ago
  6. terenzreignz
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    LOL, this is a quadratic equation in disguise

    • one year ago
  7. terenzreignz
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    cos^2 x = 1 - sin^2 x right? so we can turn it into... 1 - sin^2 x - sin^2 x = sin x

    • one year ago
  8. colorful
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    \[\cos^2x-\sin^2=1-2\sin^2x\]

    • one year ago
  9. colorful
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    oops :P ditto

    • one year ago
  10. terenzreignz
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    Oh, you can do it from here? great :)

    • one year ago
  11. colorful
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    I'm not the asker @ksaimouli can you take it from here?

    • one year ago
  12. terenzreignz
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    derp, I forgot about that (sorry)

    • one year ago
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