ksaimouli
  • ksaimouli
solve for x cos^2x-sin^2x=sin x
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ksaimouli
  • ksaimouli
\[\cos^2x-\sin^2x =sinx\]
eyust707
  • eyust707
I see trig... I see trig stuff squared... im thinkin trig identities right off the bat!
terenzreignz
  • terenzreignz
cox 2x comes to mind...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

terenzreignz
  • terenzreignz
but it's useless, I think?
eyust707
  • eyust707
no i like the thinking!
terenzreignz
  • terenzreignz
LOL, this is a quadratic equation in disguise
terenzreignz
  • terenzreignz
cos^2 x = 1 - sin^2 x right? so we can turn it into... 1 - sin^2 x - sin^2 x = sin x
anonymous
  • anonymous
\[\cos^2x-\sin^2=1-2\sin^2x\]
anonymous
  • anonymous
oops :P ditto
terenzreignz
  • terenzreignz
Oh, you can do it from here? great :)
anonymous
  • anonymous
I'm not the asker @ksaimouli can you take it from here?
terenzreignz
  • terenzreignz
derp, I forgot about that (sorry)

Looking for something else?

Not the answer you are looking for? Search for more explanations.