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Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!!
 one year ago
 one year ago
Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!!
 one year ago
 one year ago

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schmidtdancerBest ResponseYou've already chosen the best response.0
the first triangle is A=60 deg, B=46 deg, C=74 deg, sides a=9, b=7.4, c=10. I need help with the other onee!! please
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
A is the angle between a and c or what?
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
it doesn't say..
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
well there must be some picture or something that indicates whether c is touching angle A or not, otherwise all we have is...
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
There isnt a picture, i promise
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
oh I bet you are supposed to assume angle A is opposite side a, which makes this doable with the law of sines I think
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
dw:1340038642500:dw
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
. Find the bearing of the flight from C to A. a plane flies 500 km with a bearing of N 44 degrees west from B to C. the plane then flies 720 km from c to a. find thhe bearing of the flight from c to a? can you do this one too
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
how 'bout we do one at a time ;)
 one year ago

colorfulBest ResponseYou've already chosen the best response.0
first get all three angles of the triangle\[\frac a{\sin A}=\frac c{\sin C}\]solve for C then you know that B=180AC, so you will have all 3 angles, which will allow you to find the third side b\[\frac a{\sin A}=\frac b{\sin B}=\frac c{\sin C}\]
 one year ago

momo0000Best ResponseYou've already chosen the best response.0
SINA/a=SINB/b=SINC/c SIN60/9=SINC/10. SOLVING= 10SIN60/9=C 180A+C=B then sinBsinA/a=b
 one year ago
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