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 2 years ago
Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!!
 2 years ago
Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!!

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schmidtdancer
 2 years ago
Best ResponseYou've already chosen the best response.0the first triangle is A=60 deg, B=46 deg, C=74 deg, sides a=9, b=7.4, c=10. I need help with the other onee!! please

colorful
 2 years ago
Best ResponseYou've already chosen the best response.0A is the angle between a and c or what?

colorful
 2 years ago
Best ResponseYou've already chosen the best response.0well there must be some picture or something that indicates whether c is touching angle A or not, otherwise all we have is...

schmidtdancer
 2 years ago
Best ResponseYou've already chosen the best response.0There isnt a picture, i promise

colorful
 2 years ago
Best ResponseYou've already chosen the best response.0oh I bet you are supposed to assume angle A is opposite side a, which makes this doable with the law of sines I think

schmidtdancer
 2 years ago
Best ResponseYou've already chosen the best response.0. Find the bearing of the flight from C to A. a plane flies 500 km with a bearing of N 44 degrees west from B to C. the plane then flies 720 km from c to a. find thhe bearing of the flight from c to a? can you do this one too

colorful
 2 years ago
Best ResponseYou've already chosen the best response.0how 'bout we do one at a time ;)

colorful
 2 years ago
Best ResponseYou've already chosen the best response.0first get all three angles of the triangle\[\frac a{\sin A}=\frac c{\sin C}\]solve for C then you know that B=180AC, so you will have all 3 angles, which will allow you to find the third side b\[\frac a{\sin A}=\frac b{\sin B}=\frac c{\sin C}\]

momo0000
 2 years ago
Best ResponseYou've already chosen the best response.0SINA/a=SINB/b=SINC/c SIN60/9=SINC/10. SOLVING= 10SIN60/9=C 180A+C=B then sinBsinA/a=b
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