## schmidtdancer Group Title Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!! 2 years ago 2 years ago

1. schmidtdancer Group Title

the first triangle is A=60 deg, B=46 deg, C=74 deg, sides a=9, b=7.4, c=10. I need help with the other onee!! please

2. colorful Group Title

A is the angle between a and c or what?

3. schmidtdancer Group Title

it doesn't say..

4. colorful Group Title

well there must be some picture or something that indicates whether c is touching angle A or not, otherwise all we have is...

5. schmidtdancer Group Title

There isnt a picture, i promise

6. colorful Group Title

oh I bet you are supposed to assume angle A is opposite side a, which makes this doable with the law of sines I think

7. schmidtdancer Group Title

yeah

8. colorful Group Title

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9. schmidtdancer Group Title

. Find the bearing of the flight from C to A. a plane flies 500 km with a bearing of N 44 degrees west from B to C. the plane then flies 720 km from c to a. find thhe bearing of the flight from c to a? can you do this one too

10. colorful Group Title

how 'bout we do one at a time ;)

11. schmidtdancer Group Title

Ok

12. colorful Group Title

first get all three angles of the triangle$\frac a{\sin A}=\frac c{\sin C}$solve for C then you know that B=180-A-C, so you will have all 3 angles, which will allow you to find the third side b$\frac a{\sin A}=\frac b{\sin B}=\frac c{\sin C}$

13. schmidtdancer Group Title

Okay I got that

14. schmidtdancer Group Title

so....

15. momo0000 Group Title

SINA/a=SINB/b=SINC/c SIN60/9=SINC/10. SOLVING= 10SIN60/9=C 180-A+C=B then sinBsinA/a=b