## anonymous 4 years ago Please help fast, I will give medal!! Use the given information to solve the triangle. A=60 degrees, a=9, c=10. This is an ambigous case, so there needs to be 2 triangles!! thanks!!

1. anonymous

the first triangle is A=60 deg, B=46 deg, C=74 deg, sides a=9, b=7.4, c=10. I need help with the other onee!! please

2. anonymous

A is the angle between a and c or what?

3. anonymous

it doesn't say..

4. anonymous

well there must be some picture or something that indicates whether c is touching angle A or not, otherwise all we have is...

5. anonymous

There isnt a picture, i promise

6. anonymous

oh I bet you are supposed to assume angle A is opposite side a, which makes this doable with the law of sines I think

7. anonymous

yeah

8. anonymous

|dw:1340038642500:dw|

9. anonymous

. Find the bearing of the flight from C to A. a plane flies 500 km with a bearing of N 44 degrees west from B to C. the plane then flies 720 km from c to a. find thhe bearing of the flight from c to a? can you do this one too

10. anonymous

how 'bout we do one at a time ;)

11. anonymous

Ok

12. anonymous

first get all three angles of the triangle$\frac a{\sin A}=\frac c{\sin C}$solve for C then you know that B=180-A-C, so you will have all 3 angles, which will allow you to find the third side b$\frac a{\sin A}=\frac b{\sin B}=\frac c{\sin C}$

13. anonymous

Okay I got that

14. anonymous

so....

15. anonymous

SINA/a=SINB/b=SINC/c SIN60/9=SINC/10. SOLVING= 10SIN60/9=C 180-A+C=B then sinBsinA/a=b