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careless850

Solve for x in the proportion

  • one year ago
  • one year ago

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  1. careless850
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    \[\frac {9}{27x} = \frac {x}{x+3}\]

    • one year ago
  2. Nahimana
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    The bottom part is cut off on my screen >.< can you tell me what values are there?

    • one year ago
  3. careless850
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    What do you mean?

    • one year ago
  4. careless850
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    the denominator?

    • one year ago
  5. Nahimana
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    Yup, the denominators lol

    • one year ago
  6. careless850
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    the question is 9/27x = x/x+3

    • one year ago
  7. Nahimana
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    Oki lol lemme try this o.O but its been a whiile 9/27x = x/x+3 1/3x = x/x+3 (simplify 9/27) 1/3x * 3x(x+3) = x/x+3 * 3x(x+3) (multiply my the GCF) x+3 = 3x^2 (simplify) -x -x 3=3x^2-x -3 -3 3x^2-x-3=0 (to solve for x we need to use the quadratic formula) [-b +/- sqrt (b^2-4ac)]/2a (plug in values) [1 +/- sqrt(1+36)]/6 x = 1+/- sqrt37/6 x = (1 - sqrt 37)/6 = -0.847 x = (1 + sqrt 37)/6 = 1.18 x ≈ −0.85 and x ≈ 1.18

    • one year ago
  8. Nahimana
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    Darn it totally messed up my format >.<

    • one year ago
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