Here's the question you clicked on:
careless850
Solve for x in the proportion
\[\frac {9}{27x} = \frac {x}{x+3}\]
The bottom part is cut off on my screen >.< can you tell me what values are there?
Yup, the denominators lol
the question is 9/27x = x/x+3
Oki lol lemme try this o.O but its been a whiile 9/27x = x/x+3 1/3x = x/x+3 (simplify 9/27) 1/3x * 3x(x+3) = x/x+3 * 3x(x+3) (multiply my the GCF) x+3 = 3x^2 (simplify) -x -x 3=3x^2-x -3 -3 3x^2-x-3=0 (to solve for x we need to use the quadratic formula) [-b +/- sqrt (b^2-4ac)]/2a (plug in values) [1 +/- sqrt(1+36)]/6 x = 1+/- sqrt37/6 x = (1 - sqrt 37)/6 = -0.847 x = (1 + sqrt 37)/6 = 1.18 x ≈ −0.85 and x ≈ 1.18
Darn it totally messed up my format >.<