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Here's the question you clicked on:
careless850
Solve for x in the proportion
\[\frac {3}{x+2} = \frac {6}{x-1}\]
Cross multiply. \[\frac{3}{x + 2} = \frac6{x - 1}\]\[6(x + 2) = 3(x - 1)\]\[6x + 12 = 3x - 3\]\[3x = -15\]\[x = -5\]
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