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careless850
 2 years ago
Solve for x in the proportion
careless850
 2 years ago
Solve for x in the proportion

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careless850
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac {4x^{2}}{8x^{2}8x} = \frac {2}{x}\]

careless850
 2 years ago
Best ResponseYou've already chosen the best response.0Last question for my assignment.

redshift
 2 years ago
Best ResponseYou've already chosen the best response.0Have you learned crossmultiplication? If so: (x)(4x^2) = (2)(8x^2  8x) expand collect like terms isolate for x Does that help?

redshift
 2 years ago
Best ResponseYou've already chosen the best response.0(x)(4x^2) = (2)(8x^2  8x) 4x^3 = 16x^2  16x 4x^3  16x^2 + 16x = 0 4x(x^2  4x + 4) = 0 For 4x = 0: x = 0 For x^2  4x + 4 = 0: what multiplies to 4 and adds to 4: 2, 2 x^2  4x + 4 = (x  2)^2 (x  2)^2 = 0 x  2 = 0 x = 2

redshift
 2 years ago
Best ResponseYou've already chosen the best response.0But do you understand!?!?!?!
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