careless850
Solve for x in the proportion



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careless850
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\[\frac {4x^{2}}{8x^{2}8x} = \frac {2}{x}\]

careless850
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Last question for my assignment.

redshift
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Have you learned crossmultiplication?
If so:
(x)(4x^2) = (2)(8x^2  8x)
expand
collect like terms
isolate for x
Does that help?

careless850
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No.

careless850
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x = 16 and x = −16

careless850
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x = 2!

redshift
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(x)(4x^2) = (2)(8x^2  8x)
4x^3 = 16x^2  16x
4x^3  16x^2 + 16x = 0
4x(x^2  4x + 4) = 0
For 4x = 0:
x = 0
For x^2  4x + 4 = 0:
what multiplies to 4 and adds to 4: 2, 2
x^2  4x + 4 = (x  2)^2
(x  2)^2 = 0
x  2 = 0
x = 2

careless850
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Yes!

redshift
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and x = 0!

careless850
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:]

redshift
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But do you understand!?!?!?!