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Solve the equation for y. Then find the value of y for the given value of x.
3/5y4x=32y; x=9
 one year ago
 one year ago
Solve the equation for y. Then find the value of y for the given value of x. 3/5y4x=32y; x=9
 one year ago
 one year ago

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purplec16Best ResponseYou've already chosen the best response.1
What is it that you don't understand?
 one year ago

smartyBest ResponseYou've already chosen the best response.1
So you plug in the value of X and then you solve it. \[3/5y36=32y\] \[13/5y=39 \]\[Multiply 5 \to each side\] \[13y=195\] \[y=195/13\] \[y = 15\]
 one year ago

purplec16Best ResponseYou've already chosen the best response.1
Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is... \[\frac{3}{5y}4x=32y\] right?
 one year ago

purplec16Best ResponseYou've already chosen the best response.1
It ends up being a quadratic that has to be solved using the quadratic formula.
 one year ago

purplec16Best ResponseYou've already chosen the best response.1
\[\frac{3}{5y}4(9)=32y\] \[\frac{3}{5y}36=32y\] Add 36 to both sides \[\frac{3}{5y}=392y\] Multiply both sides by 5y \[3=(392y)5y\] \[3=195y10y^2\] Put the equation in standard form \[0=10y^2+195y3\]
 one year ago

purplec16Best ResponseYou've already chosen the best response.1
You do know how to use the quadratic formula right?
 one year ago

purplec16Best ResponseYou've already chosen the best response.1
Okay let me know if you have any problems! and You're welcome
 one year ago
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