A community for students.
Here's the question you clicked on:
 0 viewing
hugsandkisses
 3 years ago
Solve the equation for y. Then find the value of y for the given value of x.
3/5y4x=32y; x=9
hugsandkisses
 3 years ago
Solve the equation for y. Then find the value of y for the given value of x. 3/5y4x=32y; x=9

This Question is Closed

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1What is it that you don't understand?

smarty
 3 years ago
Best ResponseYou've already chosen the best response.1So you plug in the value of X and then you solve it. \[3/5y36=32y\] \[13/5y=39 \]\[Multiply 5 \to each side\] \[13y=195\] \[y=195/13\] \[y = 15\]

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is... \[\frac{3}{5y}4x=32y\] right?

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1It ends up being a quadratic that has to be solved using the quadratic formula.

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{3}{5y}4(9)=32y\] \[\frac{3}{5y}36=32y\] Add 36 to both sides \[\frac{3}{5y}=392y\] Multiply both sides by 5y \[3=(392y)5y\] \[3=195y10y^2\] Put the equation in standard form \[0=10y^2+195y3\]

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1You do know how to use the quadratic formula right?

purplec16
 3 years ago
Best ResponseYou've already chosen the best response.1Okay let me know if you have any problems! and You're welcome
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.