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hugsandkisses

  • 3 years ago

Solve the equation for y. Then find the value of y for the given value of x. 3/5y-4x=3-2y; x=9

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  1. purplec16
    • 3 years ago
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    What is it that you don't understand?

  2. smarty
    • 3 years ago
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    So you plug in the value of X and then you solve it. \[3/5y-36=3-2y\] \[13/5y=39 \]\[Multiply 5 \to each side\] \[13y=195\] \[y=195/13\] \[y = 15\]

  3. purplec16
    • 3 years ago
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    Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is... \[\frac{3}{5y}-4x=3-2y\] right?

  4. purplec16
    • 3 years ago
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    It ends up being a quadratic that has to be solved using the quadratic formula.

  5. hugsandkisses
    • 3 years ago
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    Thanks!

  6. purplec16
    • 3 years ago
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    \[\frac{3}{5y}-4(9)=3-2y\] \[\frac{3}{5y}-36=3-2y\] Add 36 to both sides \[\frac{3}{5y}=39-2y\] Multiply both sides by 5y \[3=(39-2y)5y\] \[3=195y-10y^2\] Put the equation in standard form \[0=-10y^2+195y-3\]

  7. purplec16
    • 3 years ago
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    You do know how to use the quadratic formula right?

  8. hugsandkisses
    • 3 years ago
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    Yeah

  9. purplec16
    • 3 years ago
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    Okay let me know if you have any problems! and You're welcome

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