## anonymous 4 years ago Solve the equation for y. Then find the value of y for the given value of x. 3/5y-4x=3-2y; x=9

1. anonymous

What is it that you don't understand?

2. anonymous

So you plug in the value of X and then you solve it. $3/5y-36=3-2y$ $13/5y=39$$Multiply 5 \to each side$ $13y=195$ $y=195/13$ $y = 15$

3. anonymous

Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is... $\frac{3}{5y}-4x=3-2y$ right?

4. anonymous

It ends up being a quadratic that has to be solved using the quadratic formula.

5. anonymous

Thanks!

6. anonymous

$\frac{3}{5y}-4(9)=3-2y$ $\frac{3}{5y}-36=3-2y$ Add 36 to both sides $\frac{3}{5y}=39-2y$ Multiply both sides by 5y $3=(39-2y)5y$ $3=195y-10y^2$ Put the equation in standard form $0=-10y^2+195y-3$

7. anonymous

You do know how to use the quadratic formula right?

8. anonymous

Yeah

9. anonymous

Okay let me know if you have any problems! and You're welcome