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anonymous
 3 years ago
Solve the equation for y. Then find the value of y for the given value of x.
3/5y4x=32y; x=9
anonymous
 3 years ago
Solve the equation for y. Then find the value of y for the given value of x. 3/5y4x=32y; x=9

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is it that you don't understand?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So you plug in the value of X and then you solve it. \[3/5y36=32y\] \[13/5y=39 \]\[Multiply 5 \to each side\] \[13y=195\] \[y=195/13\] \[y = 15\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is... \[\frac{3}{5y}4x=32y\] right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It ends up being a quadratic that has to be solved using the quadratic formula.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{5y}4(9)=32y\] \[\frac{3}{5y}36=32y\] Add 36 to both sides \[\frac{3}{5y}=392y\] Multiply both sides by 5y \[3=(392y)5y\] \[3=195y10y^2\] Put the equation in standard form \[0=10y^2+195y3\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You do know how to use the quadratic formula right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay let me know if you have any problems! and You're welcome
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