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KimJ

  • 3 years ago

Im working on this problem: 9. Differentiate H(z) = 2^1-6z

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  1. mathslover
    • 3 years ago
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    d(2)-d(6z)

  2. KimJ
    • 3 years ago
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    d(2) is 0, right?

  3. mathslover
    • 3 years ago
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    yes

  4. mathslover
    • 3 years ago
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    -6 is the answer

  5. KimJ
    • 3 years ago
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    No its not. The answer is -6(1-6z) ln(2).

  6. KimJ
    • 3 years ago
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    But I have no idea why there is a natural log.

  7. mathslover
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=%20Differentiate%20%20H(z)%20%3D%202%5E1-6z&t=crmtb01

  8. mathslover
    • 3 years ago
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    i am right according to wolfram alpha ...see steps

  9. KimJ
    • 3 years ago
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    Maybe I should have typed H(z) = 2^(1-6z)

  10. mathslover
    • 3 years ago
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    check that what is the correct ans.

  11. KimJ
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=differentiate+H%28z%29+%3D+2%5E%281-6z%29

  12. KimJ
    • 3 years ago
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    this was my fault for not writing the problem correctly

  13. mathslover
    • 3 years ago
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    ok ... so u got the correct answer ?

  14. KimJ
    • 3 years ago
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    Yes.

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