anonymous
  • anonymous
Im working on this problem: 9. Differentiate H(z) = 2^1-6z
Mathematics
schrodinger
  • schrodinger
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mathslover
  • mathslover
d(2)-d(6z)
anonymous
  • anonymous
d(2) is 0, right?
mathslover
  • mathslover
yes

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mathslover
  • mathslover
-6 is the answer
anonymous
  • anonymous
No its not. The answer is -6(1-6z) ln(2).
anonymous
  • anonymous
But I have no idea why there is a natural log.
mathslover
  • mathslover
http://www.wolframalpha.com/input/?i=%20Differentiate%20%20H(z)%20%3D%202%5E1-6z&t=crmtb01
mathslover
  • mathslover
i am right according to wolfram alpha ...see steps
anonymous
  • anonymous
Maybe I should have typed H(z) = 2^(1-6z)
mathslover
  • mathslover
check that what is the correct ans.
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=differentiate+H%28z%29+%3D+2%5E%281-6z%29
anonymous
  • anonymous
this was my fault for not writing the problem correctly
mathslover
  • mathslover
ok ... so u got the correct answer ?
anonymous
  • anonymous
Yes.

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