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KimJ

Im working on this problem: 9. Differentiate H(z) = 2^1-6z

  • one year ago
  • one year ago

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  1. mathslover
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    d(2)-d(6z)

    • one year ago
  2. KimJ
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    d(2) is 0, right?

    • one year ago
  3. mathslover
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    yes

    • one year ago
  4. mathslover
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    -6 is the answer

    • one year ago
  5. KimJ
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    No its not. The answer is -6(1-6z) ln(2).

    • one year ago
  6. KimJ
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    But I have no idea why there is a natural log.

    • one year ago
  7. mathslover
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    http://www.wolframalpha.com/input/?i=%20Differentiate%20%20H(z)%20%3D%202%5E1-6z&t=crmtb01

    • one year ago
  8. mathslover
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    i am right according to wolfram alpha ...see steps

    • one year ago
  9. KimJ
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    Maybe I should have typed H(z) = 2^(1-6z)

    • one year ago
  10. mathslover
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    check that what is the correct ans.

    • one year ago
  11. KimJ
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    http://www.wolframalpha.com/input/?i=differentiate+H%28z%29+%3D+2%5E%281-6z%29

    • one year ago
  12. KimJ
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    this was my fault for not writing the problem correctly

    • one year ago
  13. mathslover
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    ok ... so u got the correct answer ?

    • one year ago
  14. KimJ
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    Yes.

    • one year ago
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