One man starts out from a city and walks north at the rate of 3 kilometers per hour. Three hours later, a second man starts from the same place and walks the same route at 4 kilometers per hour. How far will he have to go before he overtakes the first man?

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oops i did something wrong idk why

d of man B = 4(t+3)
like i said if they overtake then distances are the same
3t = 4(t+3)
solve for t

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