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mathslover
Group Title
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
 2 years ago
 2 years ago
mathslover Group Title
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
 2 years ago
 2 years ago

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terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Quadratic Formula*?
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
yes @terenzreignz \[\Huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
\[{\textbf{the general form of a quadratic equation is ax^2+bx+c=0 . .}}\] \[\textbf{it is known as quadratic equation since it's degree is 2 }\] HOW TO GET THE ROOT OF A QUADRATIC EQUATION : \[\huge{ax^2+bx+c=0}\] \[\huge{ax^2+bx=c}\] \[\huge{\frac{(ax^2+bx)}{a}=\frac{c}{a}}\] \[\huge{x^2+\frac{bx}{a}=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)+\frac{b^2}{4a^2}=\frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{(x+\frac{b}{2a})^2 = \frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{x+\frac{b}{2a}=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}}\] \[\huge{x=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\pm\sqrt{\frac{b^24ac}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Good work, mathslover, I appreciate your tutorial :)
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
thanks a lot @ParthKohli
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
Please prefer the LaTeX for better proof and for no mistakes
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Great job @mathslover!
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
hanks @rebeccaskell94
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
*thanks @rebeccaskell94
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
You are very welcome
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@mathslover wat is ur intention by posting this!
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
to just make you all aware with quadratic equation
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
I am going to post some more interesting things about this
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
plz go ahead
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
i will but after some time. .. doing some research work :)
 2 years ago

wdkekefkjrgjr Group TitleBest ResponseYou've already chosen the best response.0
fhjjfjfjjfjgkhkjkjhk h kh khkghkghkhhkgffgfg
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
@wdkekefkjrgjr dont post such comments
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
i m posting more interesting things about quadratic equation as a new question
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
http://openstudy.com/study#/updates/4fe09fa0e4b06e92b86fbb47
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.0
k! thanx a lot @mathslover :)
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.18
Ur welcome @jiteshmeghwal9 Best of Luck
 2 years ago
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