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Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
 one year ago
 one year ago
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
 one year ago
 one year ago

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terenzreignzBest ResponseYou've already chosen the best response.0
Quadratic Formula*?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
yes @terenzreignz \[\Huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
\[{\textbf{the general form of a quadratic equation is ax^2+bx+c=0 . .}}\] \[\textbf{it is known as quadratic equation since it's degree is 2 }\] HOW TO GET THE ROOT OF A QUADRATIC EQUATION : \[\huge{ax^2+bx+c=0}\] \[\huge{ax^2+bx=c}\] \[\huge{\frac{(ax^2+bx)}{a}=\frac{c}{a}}\] \[\huge{x^2+\frac{bx}{a}=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)+\frac{b^2}{4a^2}=\frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{(x+\frac{b}{2a})^2 = \frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{x+\frac{b}{2a}=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}}\] \[\huge{x=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\pm\sqrt{\frac{b^24ac}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Good work, mathslover, I appreciate your tutorial :)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
thanks a lot @ParthKohli
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
Please prefer the LaTeX for better proof and for no mistakes
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.0
Great job @mathslover!
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
hanks @rebeccaskell94
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
*thanks @rebeccaskell94
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.0
You are very welcome
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
@mathslover wat is ur intention by posting this!
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
to just make you all aware with quadratic equation
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
I am going to post some more interesting things about this
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
i will but after some time. .. doing some research work :)
 one year ago

wdkekefkjrgjrBest ResponseYou've already chosen the best response.0
fhjjfjfjjfjgkhkjkjhk h kh khkghkghkhhkgffgfg
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
@wdkekefkjrgjr dont post such comments
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
i m posting more interesting things about quadratic equation as a new question
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
http://openstudy.com/study#/updates/4fe09fa0e4b06e92b86fbb47
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.0
k! thanx a lot @mathslover :)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.18
Ur welcome @jiteshmeghwal9 Best of Luck
 one year ago
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