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 2 years ago
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
 2 years ago
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me

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terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.0Quadratic Formula*?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18yes @terenzreignz \[\Huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18\[{\textbf{the general form of a quadratic equation is ax^2+bx+c=0 . .}}\] \[\textbf{it is known as quadratic equation since it's degree is 2 }\] HOW TO GET THE ROOT OF A QUADRATIC EQUATION : \[\huge{ax^2+bx+c=0}\] \[\huge{ax^2+bx=c}\] \[\huge{\frac{(ax^2+bx)}{a}=\frac{c}{a}}\] \[\huge{x^2+\frac{bx}{a}=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)+\frac{b^2}{4a^2}=\frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{(x+\frac{b}{2a})^2 = \frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{x+\frac{b}{2a}=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}}\] \[\huge{x=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\pm\sqrt{\frac{b^24ac}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Good work, mathslover, I appreciate your tutorial :)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18thanks a lot @ParthKohli

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18Please prefer the LaTeX for better proof and for no mistakes

rebeccaskell94
 2 years ago
Best ResponseYou've already chosen the best response.0Great job @mathslover!

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18hanks @rebeccaskell94

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18*thanks @rebeccaskell94

rebeccaskell94
 2 years ago
Best ResponseYou've already chosen the best response.0You are very welcome

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0@mathslover wat is ur intention by posting this!

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18to just make you all aware with quadratic equation

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18I am going to post some more interesting things about this

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18i will but after some time. .. doing some research work :)

wdkekefkjrgjr
 2 years ago
Best ResponseYou've already chosen the best response.0fhjjfjfjjfjgkhkjkjhk h kh khkghkghkhhkgffgfg

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18@wdkekefkjrgjr dont post such comments

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18i m posting more interesting things about quadratic equation as a new question

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18http://openstudy.com/study#/updates/4fe09fa0e4b06e92b86fbb47

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0k! thanx a lot @mathslover :)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18Ur welcome @jiteshmeghwal9 Best of Luck
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