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mathslover

  • 2 years ago

Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me

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  1. mathslover
    • 2 years ago
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  2. terenzreignz
    • 2 years ago
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    Quadratic Formula*?

  3. mathslover
    • 2 years ago
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    yes @terenzreignz \[\Huge{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]

  4. mathslover
    • 2 years ago
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    \[{\textbf{the general form of a quadratic equation is ax^2+bx+c=0 . .}}\] \[\textbf{it is known as quadratic equation since it's degree is 2 }\] HOW TO GET THE ROOT OF A QUADRATIC EQUATION : \[\huge{ax^2+bx+c=0}\] \[\huge{ax^2+bx=-c}\] \[\huge{\frac{(ax^2+bx)}{a}=\frac{-c}{a}}\] \[\huge{x^2+\frac{bx}{a}=\frac{-c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)=\frac{-c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)+\frac{b^2}{4a^2}=\frac{-c}{a}+\frac{b^2}{4a^2}}\] \[\huge{(x+\frac{b}{2a})^2 = \frac{-c}{a}+\frac{b^2}{4a^2}}\] \[\huge{x+\frac{b}{2a}=\pm\sqrt{\frac{-c}{a}+\frac{b^2}{4a^2}}}\] \[\huge{x=\pm\sqrt{\frac{-c}{a}+\frac{b^2}{4a^2}}-\frac{b}{2a}}\] \[\huge{x=\pm\sqrt{\frac{b^2-4ac}{4a^2}}-\frac{b}{2a}}\] \[\huge{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]

  5. ParthKohli
    • 2 years ago
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    Good work, mathslover, I appreciate your tutorial :)

  6. mathslover
    • 2 years ago
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    thanks a lot @ParthKohli

  7. mathslover
    • 2 years ago
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    Please prefer the LaTeX for better proof and for no mistakes

  8. rebeccaskell94
    • 2 years ago
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    Great job @mathslover!

  9. mathslover
    • 2 years ago
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    hanks @rebeccaskell94

  10. mathslover
    • 2 years ago
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    *thanks @rebeccaskell94

  11. rebeccaskell94
    • 2 years ago
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    You are very welcome

  12. Yahoo!
    • 2 years ago
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    @mathslover wat is ur intention by posting this!

  13. mathslover
    • 2 years ago
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    to just make you all aware with quadratic equation

  14. Yahoo!
    • 2 years ago
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    ok

  15. mathslover
    • 2 years ago
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    I am going to post some more interesting things about this

  16. Yahoo!
    • 2 years ago
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    plz go ahead

  17. mathslover
    • 2 years ago
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    i will but after some time. .. doing some research work :)

  18. wdkekefkjrgjr
    • 2 years ago
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    fhjjfjfjjfjgkhkjkjhk h kh khkghkghkhhkgffgfg

  19. mathslover
    • 2 years ago
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    @wdkekefkjrgjr dont post such comments

  20. mathslover
    • 2 years ago
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    i m posting more interesting things about quadratic equation as a new question

  21. mathslover
    • 2 years ago
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    http://openstudy.com/study#/updates/4fe09fa0e4b06e92b86fbb47

  22. jiteshmeghwal9
    • 2 years ago
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    k! thanx a lot @mathslover :)

  23. mathslover
    • 2 years ago
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    Ur welcome @jiteshmeghwal9 Best of Luck

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