A community for students.
Here's the question you clicked on:
 0 viewing
mathslover
 2 years ago
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me
mathslover
 2 years ago
Hi friends this is a small tutorial regarding the proof of quadratic equation ... this is made by me

This Question is Closed

terenzreignz
 2 years ago
Best ResponseYou've already chosen the best response.0Quadratic Formula*?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18yes @terenzreignz \[\Huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18\[{\textbf{the general form of a quadratic equation is ax^2+bx+c=0 . .}}\] \[\textbf{it is known as quadratic equation since it's degree is 2 }\] HOW TO GET THE ROOT OF A QUADRATIC EQUATION : \[\huge{ax^2+bx+c=0}\] \[\huge{ax^2+bx=c}\] \[\huge{\frac{(ax^2+bx)}{a}=\frac{c}{a}}\] \[\huge{x^2+\frac{bx}{a}=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)=\frac{c}{a}}\] \[\huge{(x)^2+2(\frac{b}{2a})(x)+\frac{b^2}{4a^2}=\frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{(x+\frac{b}{2a})^2 = \frac{c}{a}+\frac{b^2}{4a^2}}\] \[\huge{x+\frac{b}{2a}=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}}\] \[\huge{x=\pm\sqrt{\frac{c}{a}+\frac{b^2}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\pm\sqrt{\frac{b^24ac}{4a^2}}\frac{b}{2a}}\] \[\huge{x=\frac{b\pm\sqrt{b^24ac}}{2a}}\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Good work, mathslover, I appreciate your tutorial :)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18thanks a lot @ParthKohli

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18Please prefer the LaTeX for better proof and for no mistakes

rebeccaskell94
 2 years ago
Best ResponseYou've already chosen the best response.0Great job @mathslover!

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18hanks @rebeccaskell94

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18*thanks @rebeccaskell94

rebeccaskell94
 2 years ago
Best ResponseYou've already chosen the best response.0You are very welcome

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0@mathslover wat is ur intention by posting this!

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18to just make you all aware with quadratic equation

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18I am going to post some more interesting things about this

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18i will but after some time. .. doing some research work :)

wdkekefkjrgjr
 2 years ago
Best ResponseYou've already chosen the best response.0fhjjfjfjjfjgkhkjkjhk h kh khkghkghkhhkgffgfg

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18@wdkekefkjrgjr dont post such comments

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18i m posting more interesting things about quadratic equation as a new question

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18http://openstudy.com/study#/updates/4fe09fa0e4b06e92b86fbb47

jiteshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0k! thanx a lot @mathslover :)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.18Ur welcome @jiteshmeghwal9 Best of Luck
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.