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Missing something. Functions.
Let f : R > R be a function such that :
f( (x+y) /3) = [f(x) + f(y)] /3 then:
Is f(x) differentiable in R?
Is it continous?
Is f(x)/x differentiable?
 one year ago
 one year ago
Missing something. Functions. Let f : R > R be a function such that : f( (x+y) /3) = [f(x) + f(y)] /3 then: Is f(x) differentiable in R? Is it continous? Is f(x)/x differentiable?
 one year ago
 one year ago

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siddhantsharanBest ResponseYou've already chosen the best response.1
I know. It seems like that. But apparently not. As in the answer it's NOT differenciable in R.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.1
Oh i missed some info. ** f(0) = 0 , f'(0) = 3
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
How is the function f(x)=kx not differentiable on/in R. Hmm \[\lim_{h \to 0} \frac{3(x+h)  3x}{h}\]
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Am I doing something wrong?
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.1
Did you differenciatePut x=0integrate? { To get the function} Or observe? :P That works here too . I got the same thing too. I dunno whats wrong.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.1
Oh well. I guess the answer may be wrong then. All of us cant go wrong.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.1
Thanks for Helping. :)
 one year ago
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