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siddhantsharan
 3 years ago
Missing something. Functions.
Let f : R > R be a function such that :
f( (x+y) /3) = [f(x) + f(y)] /3 then:
Is f(x) differentiable in R?
Is it continous?
Is f(x)/x differentiable?
siddhantsharan
 3 years ago
Missing something. Functions. Let f : R > R be a function such that : f( (x+y) /3) = [f(x) + f(y)] /3 then: Is f(x) differentiable in R? Is it continous? Is f(x)/x differentiable?

This Question is Closed

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.1I know. It seems like that. But apparently not. As in the answer it's NOT differenciable in R.

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.1Oh i missed some info. ** f(0) = 0 , f'(0) = 3

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1How is the function f(x)=kx not differentiable on/in R. Hmm \[\lim_{h \to 0} \frac{3(x+h)  3x}{h}\]

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1Am I doing something wrong?

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.1Did you differenciatePut x=0integrate? { To get the function} Or observe? :P That works here too . I got the same thing too. I dunno whats wrong.

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.1Oh well. I guess the answer may be wrong then. All of us cant go wrong.

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.1Thanks for Helping. :)
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