A number is expressed as N=(x^2-169)+(x-13)^2
1. Factorise (x^2-169)+(x-13)^2 completely
2. Explain why N is an even number for any value of x
3. Hence, given that N=(83^2-169)+70^2, without evaluating for N, find the 2 factors of N which are between 10 and 100

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So have you expanded N first by doing (x-13)(x-13)?

And then you will collect like terms for N and then you can factor it

completely!

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