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anonymous
 4 years ago
a^2 – 5a – 20 factor completely
anonymous
 4 years ago
a^2 – 5a – 20 factor completely

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vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.0No not this time I think you have copied your question incorrectly it should be a^2  a  20 right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no it has 5 in this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i see it's prime so how do i show work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the answer \[5+\sqrt{105}/2,5\sqrt{105}/2\]

precal
 4 years ago
Best ResponseYou've already chosen the best response.0when it is prime, we just state "prime" and do not attempt to factor. Now if it said, solve then we solve using the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no because it's prime

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but it can be solved by discriminant method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it just said factor and show work so i don't think i have to use that .

precal
 4 years ago
Best ResponseYou've already chosen the best response.0correct, if the instructions were to factor write "prime" if the instructions were to solve then use the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's prime! Applying quadratic formula, we get: a^2 – 5*a – 20 = 0 a = 1, b =  5, c =  20 b^2  4*a*c = 25  4*1*(  20) = 105 a1 = (  (  5) + sqrt(105))/2 = 5/2 + (1/2)*sqrt(105) a2 = 5/2  (1/2)*sqrt(105)
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