anonymous
  • anonymous
a^2 – 5a – 20 factor completely
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
-5(4) right ?
vishweshshrimali5
  • vishweshshrimali5
No not this time I think you have copied your question incorrectly it should be a^2 - a - 20 right ?
anonymous
  • anonymous
no it has 5 in this one

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vishweshshrimali5
  • vishweshshrimali5
ok
anonymous
  • anonymous
i see it's prime so how do i show work
anonymous
  • anonymous
is the answer \[5+\sqrt{105}/2,5-\sqrt{105}/2\]
precal
  • precal
when it is prime, we just state "prime" and do not attempt to factor. Now if it said, solve then we solve using the quadratic formula
anonymous
  • anonymous
7.623,-2.623
anonymous
  • anonymous
yes or no?
anonymous
  • anonymous
no because it's prime
anonymous
  • anonymous
but it can be solved by discriminant method
anonymous
  • anonymous
it just said factor and show work so i don't think i have to use that .
precal
  • precal
correct, if the instructions were to factor write "prime" if the instructions were to solve then use the quadratic formula
anonymous
  • anonymous
It's prime! Applying quadratic formula, we get: a^2 – 5*a – 20 = 0 a = 1, b = - 5, c = - 20 b^2 - 4*a*c = 25 - 4*1*( - 20) = 105 a1 = ( - ( - 5) + sqrt(105))/2 = 5/2 + (1/2)*sqrt(105) a2 = 5/2 - (1/2)*sqrt(105)
anonymous
  • anonymous
ya??got it!

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