## tux 4 years ago Given a group of 10 men and 5 women: a) how many ways can you choose a committee with 4 members b) How many combinations of 4 have 2 men on them c) have less men than women d) if Mary and John won't serve together how many 4 members combinations are possible?

1. anonymous

a) $C _{4}^{15}=1365$

2. anonymous

b) $C_{2}^{10}\times C _{2}^{5}=450$

3. anonymous

c) $C _{1}^{10}\times C _{3}^{5}=100$

4. anonymous

d)$2\times C _{4}^{14}- C _{4}^{13}=1287$