## anonymous 4 years ago Describe the nature of the roots of the equation 2x^2 + 3x = –3.

1. anonymous

$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ a=2 b=3 c=3 subtitution and solve

2. anonymous

imaginary numbers

3. anonymous

one real root two real roots two imaginary roots cannot be determined

4. anonymous

So C? two imaginary roots?

5. anonymous

@Nancy_Lam

6. anonymous

yeah

7. anonymous

Thanks~

8. anonymous

what about: 7x^2 = 4x + 1.

9. anonymous

@sritama

10. anonymous

two imaginary roots

11. anonymous

How can you tell?

12. anonymous

For ex: x^2 – 4x + 4 = 0. how would you tell for that one?

13. anonymous

for the 2nd equation it is b

14. anonymous

7x^2 = 4x + 1 , i mean

15. anonymous

haha alright what about : x^2 – 4x + 4 = 0

16. anonymous

two real roots,and they are same

17. anonymous

x^2 – 4x + 4 = 0 (x-2)^2

18. anonymous

all you have to get from the value of $\sqrt{b^2-4ac}$

19. anonymous

Ohok. thanks!

20. anonymous

So the root of hte discriminant.

21. anonymous

if the value is negatives, roots are imaginary if positive . roots are real if 0,roots are real and same

22. anonymous

yeah