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Nancy_Lam
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{b \pm \sqrt{b^24ac}}{2a}\] a=2 b=3 c=3 subtitution and solve

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0one real root two real roots two imaginary roots cannot be determined

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0So C? two imaginary roots?

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0what about: 7x^2 = 4x + 1.

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0For ex: x^2 – 4x + 4 = 0. how would you tell for that one?

sritama
 2 years ago
Best ResponseYou've already chosen the best response.1for the 2nd equation it is b

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0haha alright what about : x^2 – 4x + 4 = 0

sritama
 2 years ago
Best ResponseYou've already chosen the best response.1two real roots,and they are same

Nancy_Lam
 2 years ago
Best ResponseYou've already chosen the best response.1x^2 – 4x + 4 = 0 (x2)^2

sritama
 2 years ago
Best ResponseYou've already chosen the best response.1all you have to get from the value of \[\sqrt{b^24ac}\]

smarty
 2 years ago
Best ResponseYou've already chosen the best response.0So the root of hte discriminant.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.1if the value is negatives, roots are imaginary if positive . roots are real if 0,roots are real and same
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