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Nancy_LamBest ResponseYou've already chosen the best response.1
\[\frac{b \pm \sqrt{b^24ac}}{2a}\] a=2 b=3 c=3 subtitution and solve
 one year ago

smartyBest ResponseYou've already chosen the best response.0
one real root two real roots two imaginary roots cannot be determined
 one year ago

smartyBest ResponseYou've already chosen the best response.0
So C? two imaginary roots?
 one year ago

smartyBest ResponseYou've already chosen the best response.0
what about: 7x^2 = 4x + 1.
 one year ago

smartyBest ResponseYou've already chosen the best response.0
For ex: x^2 – 4x + 4 = 0. how would you tell for that one?
 one year ago

sritamaBest ResponseYou've already chosen the best response.1
for the 2nd equation it is b
 one year ago

sritamaBest ResponseYou've already chosen the best response.1
7x^2 = 4x + 1 , i mean
 one year ago

smartyBest ResponseYou've already chosen the best response.0
haha alright what about : x^2 – 4x + 4 = 0
 one year ago

sritamaBest ResponseYou've already chosen the best response.1
two real roots,and they are same
 one year ago

Nancy_LamBest ResponseYou've already chosen the best response.1
x^2 – 4x + 4 = 0 (x2)^2
 one year ago

sritamaBest ResponseYou've already chosen the best response.1
all you have to get from the value of \[\sqrt{b^24ac}\]
 one year ago

smartyBest ResponseYou've already chosen the best response.0
So the root of hte discriminant.
 one year ago

sritamaBest ResponseYou've already chosen the best response.1
if the value is negatives, roots are imaginary if positive . roots are real if 0,roots are real and same
 one year ago
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