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smarty

  • 2 years ago

Describe the nature of the roots of the equation 2x^2 + 3x = –3.

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  1. Nancy_Lam
    • 2 years ago
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    \[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] a=2 b=3 c=3 subtitution and solve

  2. sritama
    • 2 years ago
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    imaginary numbers

  3. smarty
    • 2 years ago
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    one real root two real roots two imaginary roots cannot be determined

  4. smarty
    • 2 years ago
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    So C? two imaginary roots?

  5. smarty
    • 2 years ago
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    @Nancy_Lam

  6. sritama
    • 2 years ago
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    yeah

  7. smarty
    • 2 years ago
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    Thanks~

  8. smarty
    • 2 years ago
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    what about: 7x^2 = 4x + 1.

  9. smarty
    • 2 years ago
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    @sritama

  10. Nancy_Lam
    • 2 years ago
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    two imaginary roots

  11. smarty
    • 2 years ago
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    How can you tell?

  12. smarty
    • 2 years ago
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    For ex: x^2 – 4x + 4 = 0. how would you tell for that one?

  13. sritama
    • 2 years ago
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    for the 2nd equation it is b

  14. sritama
    • 2 years ago
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    7x^2 = 4x + 1 , i mean

  15. smarty
    • 2 years ago
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    haha alright what about : x^2 – 4x + 4 = 0

  16. sritama
    • 2 years ago
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    two real roots,and they are same

  17. Nancy_Lam
    • 2 years ago
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    x^2 – 4x + 4 = 0 (x-2)^2

  18. sritama
    • 2 years ago
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    all you have to get from the value of \[\sqrt{b^2-4ac}\]

  19. smarty
    • 2 years ago
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    Ohok. thanks!

  20. smarty
    • 2 years ago
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    So the root of hte discriminant.

  21. sritama
    • 2 years ago
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    if the value is negatives, roots are imaginary if positive . roots are real if 0,roots are real and same

  22. sritama
    • 2 years ago
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    yeah

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