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A man wishes to estimate the distance of a near by tower first he measure the tower from a and next from b if basis is 100m and the angle is 40 find the distance between the man and the tower?

Mathematics
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By using parallax method!
Do you have a picture/drawing of the man and the tower? :-D
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We have to find AC
You can find the length of segment AC using trigonometric functions, since we are given the length of AB and the measure of angle ACB. Since \[\tan(40)=\frac{AB}{AC}\] Solving for AC yields \[AC = \frac{AB}{\tan(40)} = \frac{100}{\tan(40)}\] Work that out using a calcuator: http://www.wolframalpha.com/input/?i=100%2Ftan%2840%29
thats where i was stuck we need to convert angle into radian
or i dont know wat is tan 40
To convert from degrees to radians (and vice-versa) Degrees to radians:\[\text{Angle in degrees} \times \frac{\pi}{180}\] Radians to degrees:\[\text{Angle in radians} \times \frac{180}{\pi}\]
You need to use the value of tan40. No other way. tan40 = 0.83
Right; you obtain the value of tan 40 from a table (or better - a scientific calculator).
hey during exam wat will i do calculators are not aloowed
Well, if the angle is not something like 0,30,45,60,90,120,135,150,180, and you are prohibited from using calculators, then most likely a table of sines/cosines/tangents will be provided.
you may use tan120 = tan3(40) and expand it forms a cubic eqn hmm..you can try to solve it but wont be that easy.. you may better make assumtion,,or use calculator,,why not leave answer in tan form ? note tan 45 = 1 and tan 30 = 1/sqrt3 = 0.6 approx so tan 40 should be something in between ,,maybe 0.8 and 0.9..hmm

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