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tristanj420
can some one help me with this?
The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference. 8/9 1.8 2
a10 = a+9d 13 = (-5)+9d 13+5 = 9d 18 = 9d 18/9 = d 2 = d
common difference is 2
thank you so much i'am talking and test that can let me pass the next grade
just give the question i'll try to solve...
okey here it is Find the 31st term of the following sequence. 9, 15, 21, ... 186 189 195
a31 = a+30d here a=9 & d=6 therefore, a31 = 9+30x6 a31 = 9+180 a31=189