Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

mahmit2012Best ResponseYou've already chosen the best response.1
dw:1340318787218:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
suppose to: ABCD is rectangular AE=AD PK and PH are perpendicular bisector EK=KC , DH=HC In conclusion: AP=BP AE=BC PE=PC <PAB=<PBA Then <PAE=<PBC Or <EAB=<CBA=90...!!!!!
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.0
Omg mahmit sir O.O
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
Hi , can you solve the problem above?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
if AD = AE, PE has to be more than PC. both cannot be same.. so question is wrong.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
u see ? think of a circle with radius AD and center at A.. since P is fixed point, its length changes as it moves along the circle..
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
PK is perpendicular bisector and shows PE=PC what's wrong?
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
no P change with E it obviously depend to E
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
wait.. im confused again.... gimme some time il get back
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
PD = PC (P is on perpendicular bisector of DC)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
i see it some what blurred way.. let me explain my logic
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
with P as center, and PD as radius draw a circle. it goes through D and C points
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
draw another circle, with A as center, and AD as radius
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1340380572369:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
Do you think points P A and E are in a straight line?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
no way lol... PAE & PBC are congruent triangles i can see that
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
the thing im trying to figure out and put is : two circles intersect at two no more than two points...
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1340381146334:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
with respect to PA straight line, if P is fixed, and PE = PD, PE and PD lie on either side of PA
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
im not sure.. if this is satisfying for u. but its ok to me to conclude that question is wrong based this....
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1340383701791:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
so if we move E to the other side of PA straight line, triangles EAP, DAP, CBP are congruent
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
when you move E should change EC perpendicular bisector then K and P will be different.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
ok did i make myself clear why i think PE should come other side of PA ? in your diagram both PE and PD are on same side of PA which is wrong
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
If you have cad to draw exactly the figure please try to figure out what happen in there? Thank you for helping and hope we will get a logical proofing after all.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1340392907050:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
dw:1340392825081:dw
 one year ago