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 2 years ago
Optimization Problems....! ==''
Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.
 2 years ago
Optimization Problems....! =='' Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.

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rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2Write an expression for the volume V in terms of x and y.

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2for me the problem is can't understand the situation..

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2am I right or not? and then?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1the shaded region will be folded to form the cuboid

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1is the answer 1 cubic feet?

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2where is y and x? don't know the answer yet.. you mean the largest volume of such situation should be 1 cubic ft ?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1yes, it is to be solved by AMGM inequality

vood
 2 years ago
Best ResponseYou've already chosen the best response.0I think \[V=y \times y \times x =y ^{2}x\]

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0@rebootkz is this in calculus chapter ?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1sir i still think the answer is 1 cubic feet

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0write out an equation for V :

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2V = (3  2x)^2(x) = (9  12x + 4x^2)(x) = 9x  12x^2 + 4x^3 V'=3(2X3)(2X1)

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0V' = 0, and find out X values

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2X=1/2 OR 3/2 V(1/2)=2 V(3/2)=0 SO IT'S 2

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1oh the balls on me,,,, i found the minimum volume :(

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2yeppp ! thanks :DDD @dg123 @ganeshie8 @vood

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2okkk !! hahaa never mind ! best answer ! hahahaha thx "D

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0lol.. why you left X = 3/2 ?

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0oh ok.. you have shown it in the above equation... im seeing now only lol

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2V = (3  2x)^2(x) = (9  12x + 4x^2)(x) = 9x  12x^2 + 4x^3 V' = 924x+12x^2=3(4x^28x+3)=3(2X3)(2X1) LET V'(X)=0 THEN ...

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0its not : let V'(X) = 0 to find where the Volume has extreme values, we are equating V' (slope of Volume function) = 0

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2yep , exactly ! anyways, i got the answer ! haha

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1340361872423:dw

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2my hw is due 7:30am ...very soon.. goshhh! I still have TWo chapters to do !!!! so ... just do simple way...!!!! thx :DDDD

vood
 2 years ago
Best ResponseYou've already chosen the best response.0I am not sure but i think that the maximum volume is 27 cubic feet

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0@vood must be jk.. we need four times the material to have that volume..

holls622
 3 months ago
Best ResponseYou've already chosen the best response.0(e) Use part (d) to write the volume as a function of x.
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