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 2 years ago
Optimization Problems....! ==''
Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.
 2 years ago
Optimization Problems....! =='' Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.

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rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2Write an expression for the volume V in terms of x and y.

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2for me the problem is can't understand the situation..

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2am I right or not? and then?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1the shaded region will be folded to form the cuboid

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1is the answer 1 cubic feet?

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2where is y and x? don't know the answer yet.. you mean the largest volume of such situation should be 1 cubic ft ?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1yes, it is to be solved by AMGM inequality

vood
 2 years ago
Best ResponseYou've already chosen the best response.0I think \[V=y \times y \times x =y ^{2}x\]

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0@rebootkz is this in calculus chapter ?

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1sir i still think the answer is 1 cubic feet

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0write out an equation for V :

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2V = (3  2x)^2(x) = (9  12x + 4x^2)(x) = 9x  12x^2 + 4x^3 V'=3(2X3)(2X1)

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0V' = 0, and find out X values

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2X=1/2 OR 3/2 V(1/2)=2 V(3/2)=0 SO IT'S 2

dg123
 2 years ago
Best ResponseYou've already chosen the best response.1oh the balls on me,,,, i found the minimum volume :(

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2yeppp ! thanks :DDD @dg123 @ganeshie8 @vood

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2okkk !! hahaa never mind ! best answer ! hahahaha thx "D

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0lol.. why you left X = 3/2 ?

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0oh ok.. you have shown it in the above equation... im seeing now only lol

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2V = (3  2x)^2(x) = (9  12x + 4x^2)(x) = 9x  12x^2 + 4x^3 V' = 924x+12x^2=3(4x^28x+3)=3(2X3)(2X1) LET V'(X)=0 THEN ...

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0its not : let V'(X) = 0 to find where the Volume has extreme values, we are equating V' (slope of Volume function) = 0

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2yep , exactly ! anyways, i got the answer ! haha

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1340361872423:dw

rebootkz
 2 years ago
Best ResponseYou've already chosen the best response.2my hw is due 7:30am ...very soon.. goshhh! I still have TWo chapters to do !!!! so ... just do simple way...!!!! thx :DDDD

vood
 2 years ago
Best ResponseYou've already chosen the best response.0I am not sure but i think that the maximum volume is 27 cubic feet

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0@vood must be jk.. we need four times the material to have that volume..

holls622
 one month ago
Best ResponseYou've already chosen the best response.0(e) Use part (d) to write the volume as a function of x.
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