Romero
State the equivalent form of



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Romero
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\[\frac{2}{3+i}\]

Romero
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\[a) \frac{3i}{4}\]
\[b) \frac{31}{5}\]
\[c) \frac{4i}{4}\]
\[d) \frac{4i}{5}\]

Romero
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I said a but I was wrong....it's suppose to be b....can anyone explain.

mukushla
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2/(3+i)=2(3i)/(3i)(3+i)=2(3i)/10=(3i)/5

mukushla
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(3i)(3+i)=9i^2=9(1)=10

Romero
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gotcha i forgot the 

Romero
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so you add the one instead of subtracting it

Romero
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thanks

mukushla
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your welcome