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julie001 Group Title

Circle S has an equation of (x – 16)2 + (y + 9)2 = 4. What is the center and radius of circle S?

  • 2 years ago
  • 2 years ago

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  1. sugargurl Group Title
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    |dw:1340399424345:dw|

    • 2 years ago
  2. ash2326 Group Title
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    A circle with center ( a, b ) and radius r has equation given as \[(x-a)^2+(y-b)^2=r^2\] We are given equation of circle as \[(x – 16)^2 + (y + 9)^2 = 4\] @julie001 Can you compare the two equations to find the center and radius?

    • 2 years ago
  3. julie001 Group Title
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    Center: (16, -9); Radius: 4 Center: (-16, 9); Radius: 2 Center: (16, -9); Radius: 2 Center: (-16, 9); Radius: 4

    • 2 years ago
  4. julie001 Group Title
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    im not sure

    • 2 years ago
  5. ash2326 Group Title
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    @sugargurl Please explain how did you get the answer?

    • 2 years ago
  6. ash2326 Group Title
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    @julie001 where you have doubt?

    • 2 years ago
  7. julie001 Group Title
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    comparintg the equations

    • 2 years ago
  8. sugargurl Group Title
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    ANSWER IS THE 2ND CHOICE..:)

    • 2 years ago
  9. julie001 Group Title
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    hoW ?

    • 2 years ago
  10. Mertsj Group Title
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    No sugargurl. Answer is NOT the second choice.

    • 2 years ago
  11. ash2326 Group Title
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    Work step by step \[(x-a)^2=(x-16)^2\] so a=16 Now you could find b and r, using the same procedure

    • 2 years ago
  12. sugargurl Group Title
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    YUO THE ANSWER IS THE 3RD CHOICE THANKS FOR CORRECTING ME @ MERTSJ

    • 2 years ago
  13. julie001 Group Title
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    @ash2326 im still lost

    • 2 years ago
  14. ash2326 Group Title
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    Did you understand how I found a?

    • 2 years ago
  15. julie001 Group Title
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    from the question ?

    • 2 years ago
  16. ash2326 Group Title
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    Yeah, standard equation of a circle is \[(x-a)^2+(y-b)^2=r^2\] and the equation given in the question is \[(x-16)^2+(y+9)^2=4\] We need to find the center (a, b) and radius r. So we compare the two equations \[(x-a)^2=(x-16)^2\] To make both sides equal a should be 16, so a=16 Now can you find b, by comparing \[(y-b)^2=(y+9)^2\]

    • 2 years ago
  17. julie001 Group Title
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    so its Center: (16, -9); Radius: 2

    • 2 years ago
  18. ash2326 Group Title
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    Could you show me your work?

    • 2 years ago
  19. Mertsj Group Title
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    There is no work to show. We know that if the equation is written in the form: \[(x-h)^2+(y-k)^2=r^2\] then the center is (h,k) and the radius is r

    • 2 years ago
  20. julie001 Group Title
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    i just plugged in the numbers with the equation

    • 2 years ago
  21. Mertsj Group Title
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    So write the given equation: \[(x-16)^2+(y-(-9))^2=2^2\] and it is immediately obvious that the center is (16,-9) and the radius is 2

    • 2 years ago
  22. julie001 Group Title
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    @Mertsj is it Center: (16, -9); Radius: 2

    • 2 years ago
  23. Mertsj Group Title
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    and it is immediately obvious that the center is (16,-9) and the radius is 2

    • 2 years ago
  24. julie001 Group Title
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    thanks !

    • 2 years ago
  25. Mertsj Group Title
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    yw

    • 2 years ago
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