anonymous
  • anonymous
A downward force of 8.4N is exerted on a -8.8uC charge. What are the magnitude and direction of the electric field?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[E=F/q\] E= 8.4N/ -8.8 X 10^6 C= Upward
anonymous
  • anonymous
what would be the unit?
anonymous
  • anonymous
thank you very much

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

prakharluv
  • prakharluv
its unit will be Newton per coulomb
prakharluv
  • prakharluv
E=F/q E=8.4 N/-8.8*10^6=-9.5*10^-7 N/C -ve sign indicates the direction of Electric field is vertically upward.
anonymous
  • anonymous
if the sign is positive the direction will be downward?
prakharluv
  • prakharluv
yup
anonymous
  • anonymous
okay now i finally got the problem thank you. but this one is different: An electron is released from the rest in a uniform electric field and accelerates to the north at the rate of 115m/s^2. What are the magnitude and direction of electric field (E)?
prakharluv
  • prakharluv
we know that F=ma, so on putting the value of m and a you will get force... and we know that the charge on electron...simply put all the values in eqn. E=F/q=ma/q you will get ur ans
anonymous
  • anonymous
the acceleration would be_115m/s^2 right? what would be the mass? and our q would be the electrons charge?
prakharluv
  • prakharluv
mass of electron is 9.1*10^-31kg and charge on electron is -1.6*10^-19C
prakharluv
  • prakharluv
ans will be -6.5*10^-48 N /C
anonymous
  • anonymous
this: (115m/s^2) ( 9.1*10^-31kg) divided by -1.6*10^-19C ?
prakharluv
  • prakharluv
yeah
anonymous
  • anonymous
thank you so much
anonymous
  • anonymous
how did you get this ( 9.1*10^-31kg) ?
prakharluv
  • prakharluv
it is calculated value..you may learn it. u may also learn the charges and masses of another sub atomic particles
anonymous
  • anonymous
is it constant? can u show me how did u get it?
prakharluv
  • prakharluv
yes it is constant... and for further information please concern with wikipedia here u will get ur ans...
anonymous
  • anonymous
how did u get the exponent -48? i got -10 ?
anonymous
  • anonymous
yes, -10
anonymous
  • anonymous
how about this: What are the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2360N/C that points due East. the charge of electron is 1.6 x10^(-19) ? how come? Force=electric field x charge electric field=2360
prakharluv
  • prakharluv
what are u asking alfers101?
anonymous
  • anonymous
The charge of an electron is always the same, it is a given ( and it should be negative though). You have to plug in. Pay attention to the units, write the units of the given. You have to still determine the direction. F= qE; plug in ; and since it is negative it should be in the opposite direction.

Looking for something else?

Not the answer you are looking for? Search for more explanations.