A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
A downward force of 8.4N is exerted on a 8.8uC charge. What are the magnitude and direction of the electric field?
 2 years ago
A downward force of 8.4N is exerted on a 8.8uC charge. What are the magnitude and direction of the electric field?

This Question is Closed

watsgood
 2 years ago
Best ResponseYou've already chosen the best response.1\[E=F/q\] E= 8.4N/ 8.8 X 10^6 C= Upward

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0what would be the unit?

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0its unit will be Newton per coulomb

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0E=F/q E=8.4 N/8.8*10^6=9.5*10^7 N/C ve sign indicates the direction of Electric field is vertically upward.

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0if the sign is positive the direction will be downward?

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0okay now i finally got the problem thank you. but this one is different: An electron is released from the rest in a uniform electric field and accelerates to the north at the rate of 115m/s^2. What are the magnitude and direction of electric field (E)?

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0we know that F=ma, so on putting the value of m and a you will get force... and we know that the charge on electron...simply put all the values in eqn. E=F/q=ma/q you will get ur ans

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0the acceleration would be_115m/s^2 right? what would be the mass? and our q would be the electrons charge?

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0mass of electron is 9.1*10^31kg and charge on electron is 1.6*10^19C

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0ans will be 6.5*10^48 N /C

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0this: (115m/s^2) ( 9.1*10^31kg) divided by 1.6*10^19C ?

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0how did you get this ( 9.1*10^31kg) ?

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0it is calculated value..you may learn it. u may also learn the charges and masses of another sub atomic particles

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0is it constant? can u show me how did u get it?

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0yes it is constant... and for further information please concern with wikipedia here u will get ur ans...

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0how did u get the exponent 48? i got 10 ?

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.0how about this: What are the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2360N/C that points due East. the charge of electron is 1.6 x10^(19) ? how come? Force=electric field x charge electric field=2360

prakharluv
 2 years ago
Best ResponseYou've already chosen the best response.0what are u asking alfers101?

watsgood
 2 years ago
Best ResponseYou've already chosen the best response.1The charge of an electron is always the same, it is a given ( and it should be negative though). You have to plug in. Pay attention to the units, write the units of the given. You have to still determine the direction. F= qE; plug in ; and since it is negative it should be in the opposite direction.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.