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What is the magnitude if the acceleration experienced by an electron in an E of 750 N/C ? How does the direction of the acceleration depende in the direction of the field at this point?

Mathematics
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F=m.a
F=E.Q
two formula?

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Other answers:

a=E.Q/m
Q is the electron charge,and m is the mass of electron
(750N/C) (9.1x10^-31) divided by ???
direction?
am i right with the Q ?
no.. q=1.6*10^-19 m=9.1*10^-31
then the e is 750 N/C ?
yup
what if -1.6*10^-19 ? what is the difference between this negative and the positive 1.6*10^-19 ?
yeah...i forgot...both electron and proton have the same charge.. for electron...it's negative...and for proton it's positive.
so for electron..-1.6*10^-19
so i will use negative in this problem? because of electron?
acceleration has opposite direction of field
so you mean, even if it is electron, it has acceleration so it will be positive?
the positive field will attract the electron
oh okay that means, when it attracts the electron it will be positive ?
how did u get the mass= 9.1*10^-31 ?
use google
is it constant? i cant find it on google. :( its shows Kinetic Energy and Electric Field
https://www.google.com.br/search?aq=f&sugexp=chrome,mod=10&sourceid=chrome&ie=UTF-8&q=mass+of+electron
wow thank you so much. God bless you :)

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