alfers101
What is the magnitude if the acceleration experienced by an electron in an E of 750 N/C ? How does the direction of the acceleration depende in the direction of the field at this point?
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alfers101
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two formula?
RaphaelFilgueiras
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Q is the electron charge,and m is the mass of electron
alfers101
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(750N/C) (9.1x10^-31) divided by ???
anusha.p
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direction?
alfers101
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am i right with the Q ?
anusha.p
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no..
q=1.6*10^-19
m=9.1*10^-31
alfers101
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then the e is 750 N/C ?
anusha.p
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yup
alfers101
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what if -1.6*10^-19 ? what is the difference between this negative and the positive 1.6*10^-19 ?
anusha.p
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yeah...i forgot...both electron and proton have the same charge..
for electron...it's negative...and for proton it's positive.
anusha.p
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so for electron..-1.6*10^-19
alfers101
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so i will use negative in this problem? because of electron?
RaphaelFilgueiras
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acceleration has opposite direction of field
alfers101
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so you mean, even if it is electron, it has acceleration so it will be positive?
RaphaelFilgueiras
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the positive field will attract the electron
alfers101
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oh okay that means, when it attracts the electron it will be positive ?
alfers101
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how did u get the mass= 9.1*10^-31 ?
RaphaelFilgueiras
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use google
alfers101
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is it constant? i cant find it on google. :( its shows Kinetic Energy and Electric Field
alfers101
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wow thank you so much. God bless you :)