## alfers101 3 years ago What is the magnitude if the acceleration experienced by an electron in an E of 750 N/C ? How does the direction of the acceleration depende in the direction of the field at this point?

1. RaphaelFilgueiras

F=m.a

2. RaphaelFilgueiras

F=E.Q

3. alfers101

two formula?

4. RaphaelFilgueiras

a=E.Q/m

5. RaphaelFilgueiras

Q is the electron charge,and m is the mass of electron

6. alfers101

(750N/C) (9.1x10^-31) divided by ???

7. anusha.p

direction?

8. alfers101

am i right with the Q ?

9. anusha.p

no.. q=1.6*10^-19 m=9.1*10^-31

10. alfers101

then the e is 750 N/C ?

11. anusha.p

yup

12. alfers101

what if -1.6*10^-19 ? what is the difference between this negative and the positive 1.6*10^-19 ?

13. anusha.p

yeah...i forgot...both electron and proton have the same charge.. for electron...it's negative...and for proton it's positive.

14. anusha.p

so for electron..-1.6*10^-19

15. alfers101

so i will use negative in this problem? because of electron?

16. RaphaelFilgueiras

acceleration has opposite direction of field

17. alfers101

so you mean, even if it is electron, it has acceleration so it will be positive?

18. RaphaelFilgueiras

the positive field will attract the electron

19. alfers101

oh okay that means, when it attracts the electron it will be positive ?

20. alfers101

how did u get the mass= 9.1*10^-31 ?

21. RaphaelFilgueiras

22. alfers101

is it constant? i cant find it on google. :( its shows Kinetic Energy and Electric Field

23. RaphaelFilgueiras
24. alfers101

wow thank you so much. God bless you :)