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The numerator of an improper fraction is 4 more than the denominator. When the numerator is decreased by 3 and the denominator is decreased by 1, the fraction is decreased by 3/10. Find the original improper fraction.
 one year ago
 one year ago
The numerator of an improper fraction is 4 more than the denominator. When the numerator is decreased by 3 and the denominator is decreased by 1, the fraction is decreased by 3/10. Find the original improper fraction.
 one year ago
 one year ago

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FoolAroundMathBest ResponseYou've already chosen the best response.2
Let the denominator of original fraction be x numerator of original fraction = x+4 new numerator = (x+4)3 = x+1 new denominator = x1 new fraction = original fraction  3/10 \[\frac{x+1}{x1} = \frac{x+4}{x}  \frac{3}{10}\] can you solve this now?
 one year ago

robtobeyBest ResponseYou've already chosen the best response.0
Let the following be the original improper fraction:\[\frac{x+4}{x} \]Solve the following for x:\[\frac{x+43}{x1}\text{=}\frac{x+4}{x}\frac{3}{10}\]\[\left\{x=\frac{8}{3},x=5\right\} \]Calculate the value of the original fraction when x=8/3\[\frac{4+x}{x}\text{=}\frac{4+\frac{8}{3}}{\frac{8}{3}}\text{=}\frac{5}{2}\]and x = 5\[\frac{4+5}{5}=\frac{9}{5} \]Assume that the answer is \[\frac{9}{5} \]and verify it's validity:\[\frac{9}{5}\frac{3}{10}\text{ = }\frac{93}{51}\]\[\frac{3}{2}\text{ = }\frac{3}{2}\]Although 5/2 is another solution to the equation, it will not pass the validity test.
 one year ago
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