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FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1For any parabola of the form \(ax^2+bx+c=0 \) the vertex will be at \( \large \left(\frac b {2a} , \frac {b^24ac}{4a}\right) \).Equation of line of symmetry will be at \(x=\frac b {2a} \) Maximum and minimum values will be at \( \large \left(\frac b {2a} , \frac {b^24ac}{4a}\right) \) and \( \large \left(\frac b {2a} , \frac {b^24ac}{4a}\right) \) for \(a<0\) and \(a>0\) respectively.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0@FoolForMath but that does not lead to the correct answer

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1i think there is no minimum value

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1it's unbounded

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1For this problem there will be no minimum values.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0can we do this like : 45x4x^2 44(x^2+5x/4) 44(x^2+5x4 +25/64) + 25/16 ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0is this the correct method ?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1340428823754:dw

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1just maximum value

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.044(x^2+5x4 +25/64) + 25/16 89/164((x+5/8)^2) hence it as min. value of 89/16 at x =5/8 is it right ?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1THIS FUNCTION HAS NO MINIMUM VALUE

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=45x4x%5E2&t=crmtb01 i am getting right according to this but it may be wrong please have a look

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1Lets try to plot this function graphically,

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1ok try x = 10000

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1when do you think the minimum value will be achieved?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0can u tell m not soo good

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1every x you get i will pick one,that that my function will be less than yours

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, for every minimum you find I can find another x which gives a lesser value ...

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0thanks a lot every one
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