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anonymous
 3 years ago
1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.
2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.
anonymous
 3 years ago
1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4. 2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is the degree if you multiply x^2*(x+2) ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge x^2(x+2) = \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just multiply it out...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not quite... \[\large x^2(x+2)=x^3+2x \]... agreed?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so that's a third degree polynomial.. and what is the remainder if we take \(\large x^3+2x \) divided by \(\large x+2 \) ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0remember we just multiplied it out to get that third degree polynomial...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0confused...................

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if I ask you to multipl 2 times 3, what's the product?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now... what's the remainder if I ask you 6 divided by 3 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's what i was asking in when we were working with the polynomial x^3 + 2x... the remainder when \(\large x^3+2x \) divided by \(\large x+2 \) is zero....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0good... but we want a remainder of 4.... so what do you think we need to do?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340429487175:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we need to stick something in that box so that our remainder is 4....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok... how 'bout this....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah what goes in the box?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok... sorry.. i made some typos up there... but this should be more clear...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340430131260:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340430256983:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0see the question mark? what should it be in order for our remainder to be 4?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes... i'm sorry i shuda done this way first.....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340430491392:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay gottcha thats the equation thats is a third degree polynomial that when divided by x + 2 has a remainder of –4. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes...:) again.... sorry....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for sticking with me....:)
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