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sara1234 Group Title

1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4. 2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.

  • 2 years ago
  • 2 years ago

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  1. dpaInc Group Title
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    what is the degree if you multiply x^2*(x+2) ?

    • 2 years ago
  2. dpaInc Group Title
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    \[\huge x^2(x+2) = \]

    • 2 years ago
  3. dpaInc Group Title
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    just multiply it out...

    • 2 years ago
  4. dpaInc Group Title
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    not quite... \[\large x^2(x+2)=x^3+2x \]... agreed?

    • 2 years ago
  5. sara1234 Group Title
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    yes

    • 2 years ago
  6. dpaInc Group Title
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    so that's a third degree polynomial.. and what is the remainder if we take \(\large x^3+2x \) divided by \(\large x+2 \) ???

    • 2 years ago
  7. dpaInc Group Title
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    remember we just multiplied it out to get that third degree polynomial...

    • 2 years ago
  8. sara1234 Group Title
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    -4

    • 2 years ago
  9. dpaInc Group Title
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    no...

    • 2 years ago
  10. sara1234 Group Title
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    confused...................

    • 2 years ago
  11. dpaInc Group Title
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    if I ask you to multipl 2 times 3, what's the product?

    • 2 years ago
  12. dpaInc Group Title
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    **multiply...

    • 2 years ago
  13. sara1234 Group Title
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    6

    • 2 years ago
  14. dpaInc Group Title
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    now... what's the remainder if I ask you 6 divided by 3 ?

    • 2 years ago
  15. sara1234 Group Title
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    0

    • 2 years ago
  16. dpaInc Group Title
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    that's what i was asking in when we were working with the polynomial x^3 + 2x... the remainder when \(\large x^3+2x \) divided by \(\large x+2 \) is zero....

    • 2 years ago
  17. dpaInc Group Title
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    still with me?

    • 2 years ago
  18. sara1234 Group Title
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    yeah

    • 2 years ago
  19. dpaInc Group Title
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    good... but we want a remainder of -4.... so what do you think we need to do?

    • 2 years ago
  20. sara1234 Group Title
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    not sure

    • 2 years ago
  21. dpaInc Group Title
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    |dw:1340429487175:dw|

    • 2 years ago
  22. dpaInc Group Title
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    we need to stick something in that box so that our remainder is -4....

    • 2 years ago
  23. dpaInc Group Title
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    take a wild guess...

    • 2 years ago
  24. dpaInc Group Title
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    ok... how 'bout this....

    • 2 years ago
  25. sara1234 Group Title
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    ???

    • 2 years ago
  26. dpaInc Group Title
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    still there sara?

    • 2 years ago
  27. sara1234 Group Title
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    yeah what goes in the box?

    • 2 years ago
  28. dpaInc Group Title
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    ok... sorry.. i made some typos up there... but this should be more clear...

    • 2 years ago
  29. dpaInc Group Title
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    |dw:1340430131260:dw|

    • 2 years ago
  30. dpaInc Group Title
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    |dw:1340430256983:dw|

    • 2 years ago
  31. dpaInc Group Title
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    see the question mark? what should it be in order for our remainder to be -4?

    • 2 years ago
  32. sara1234 Group Title
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    -4

    • 2 years ago
  33. dpaInc Group Title
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    yes... i'm sorry i shuda done this way first.....

    • 2 years ago
  34. dpaInc Group Title
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    |dw:1340430491392:dw|

    • 2 years ago
  35. sara1234 Group Title
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    okay gottcha thats the equation thats is a third degree polynomial that when divided by x + 2 has a remainder of –4. :)

    • 2 years ago
  36. dpaInc Group Title
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    yes...:) again.... sorry....

    • 2 years ago
  37. sara1234 Group Title
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    its okay

    • 2 years ago
  38. dpaInc Group Title
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    thanks for sticking with me....:)

    • 2 years ago
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is replying to Can someone tell me what button the professor is hitting...

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