1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.
2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.

- anonymous

- jamiebookeater

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

what is the degree if you multiply x^2*(x+2) ?

- anonymous

\[\huge x^2(x+2) = \]

- anonymous

just multiply it out...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

not quite...
\[\large x^2(x+2)=x^3+2x \]... agreed?

- anonymous

yes

- anonymous

so that's a third degree polynomial.. and what is the remainder if we take
\(\large x^3+2x \) divided by \(\large x+2 \) ???

- anonymous

remember we just multiplied it out to get that third degree polynomial...

- anonymous

-4

- anonymous

no...

- anonymous

confused...................

- anonymous

if I ask you to multipl 2 times 3, what's the product?

- anonymous

**multiply...

- anonymous

6

- anonymous

now... what's the remainder if I ask you 6 divided by 3 ?

- anonymous

0

- anonymous

that's what i was asking in when we were working with the polynomial x^3 + 2x...
the remainder when \(\large x^3+2x \) divided by \(\large x+2 \) is zero....

- anonymous

still with me?

- anonymous

yeah

- anonymous

good... but we want a remainder of -4....
so what do you think we need to do?

- anonymous

not sure

- anonymous

|dw:1340429487175:dw|

- anonymous

we need to stick something in that box so that our remainder is -4....

- anonymous

take a wild guess...

- anonymous

ok... how 'bout this....

- anonymous

???

- anonymous

still there sara?

- anonymous

yeah what goes in the box?

- anonymous

ok... sorry.. i made some typos up there... but this should be more clear...

- anonymous

|dw:1340430131260:dw|

- anonymous

|dw:1340430256983:dw|

- anonymous

see the question mark? what should it be in order for our remainder to be -4?

- anonymous

-4

- anonymous

yes... i'm sorry i shuda done this way first.....

- anonymous

|dw:1340430491392:dw|

- anonymous

okay gottcha thats the equation thats is a third degree polynomial that when divided by x + 2 has a remainder of –4. :)

- anonymous

yes...:)
again.... sorry....

- anonymous

its okay

- anonymous

thanks for sticking with me....:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.