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sara1234

  • 2 years ago

1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4. 2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.

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  1. dpaInc
    • 2 years ago
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    what is the degree if you multiply x^2*(x+2) ?

  2. dpaInc
    • 2 years ago
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    \[\huge x^2(x+2) = \]

  3. dpaInc
    • 2 years ago
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    just multiply it out...

  4. dpaInc
    • 2 years ago
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    not quite... \[\large x^2(x+2)=x^3+2x \]... agreed?

  5. sara1234
    • 2 years ago
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    yes

  6. dpaInc
    • 2 years ago
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    so that's a third degree polynomial.. and what is the remainder if we take \(\large x^3+2x \) divided by \(\large x+2 \) ???

  7. dpaInc
    • 2 years ago
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    remember we just multiplied it out to get that third degree polynomial...

  8. sara1234
    • 2 years ago
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    -4

  9. dpaInc
    • 2 years ago
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    no...

  10. sara1234
    • 2 years ago
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    confused...................

  11. dpaInc
    • 2 years ago
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    if I ask you to multipl 2 times 3, what's the product?

  12. dpaInc
    • 2 years ago
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    **multiply...

  13. sara1234
    • 2 years ago
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    6

  14. dpaInc
    • 2 years ago
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    now... what's the remainder if I ask you 6 divided by 3 ?

  15. sara1234
    • 2 years ago
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    0

  16. dpaInc
    • 2 years ago
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    that's what i was asking in when we were working with the polynomial x^3 + 2x... the remainder when \(\large x^3+2x \) divided by \(\large x+2 \) is zero....

  17. dpaInc
    • 2 years ago
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    still with me?

  18. sara1234
    • 2 years ago
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    yeah

  19. dpaInc
    • 2 years ago
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    good... but we want a remainder of -4.... so what do you think we need to do?

  20. sara1234
    • 2 years ago
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    not sure

  21. dpaInc
    • 2 years ago
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    |dw:1340429487175:dw|

  22. dpaInc
    • 2 years ago
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    we need to stick something in that box so that our remainder is -4....

  23. dpaInc
    • 2 years ago
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    take a wild guess...

  24. dpaInc
    • 2 years ago
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    ok... how 'bout this....

  25. sara1234
    • 2 years ago
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    ???

  26. dpaInc
    • 2 years ago
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    still there sara?

  27. sara1234
    • 2 years ago
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    yeah what goes in the box?

  28. dpaInc
    • 2 years ago
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    ok... sorry.. i made some typos up there... but this should be more clear...

  29. dpaInc
    • 2 years ago
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    |dw:1340430131260:dw|

  30. dpaInc
    • 2 years ago
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    |dw:1340430256983:dw|

  31. dpaInc
    • 2 years ago
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    see the question mark? what should it be in order for our remainder to be -4?

  32. sara1234
    • 2 years ago
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    -4

  33. dpaInc
    • 2 years ago
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    yes... i'm sorry i shuda done this way first.....

  34. dpaInc
    • 2 years ago
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    |dw:1340430491392:dw|

  35. sara1234
    • 2 years ago
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    okay gottcha thats the equation thats is a third degree polynomial that when divided by x + 2 has a remainder of –4. :)

  36. dpaInc
    • 2 years ago
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    yes...:) again.... sorry....

  37. sara1234
    • 2 years ago
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    its okay

  38. dpaInc
    • 2 years ago
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    thanks for sticking with me....:)

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