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1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.
2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.
 one year ago
 one year ago
1. Create your own third degree polynomial that when divided by x + 2 has a remainder of –4. 2. Create your own division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.
 one year ago
 one year ago

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dpaIncBest ResponseYou've already chosen the best response.5
what is the degree if you multiply x^2*(x+2) ?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
just multiply it out...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
not quite... \[\large x^2(x+2)=x^3+2x \]... agreed?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
so that's a third degree polynomial.. and what is the remainder if we take \(\large x^3+2x \) divided by \(\large x+2 \) ???
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
remember we just multiplied it out to get that third degree polynomial...
 one year ago

sara1234Best ResponseYou've already chosen the best response.1
confused...................
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
if I ask you to multipl 2 times 3, what's the product?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
now... what's the remainder if I ask you 6 divided by 3 ?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
that's what i was asking in when we were working with the polynomial x^3 + 2x... the remainder when \(\large x^3+2x \) divided by \(\large x+2 \) is zero....
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
good... but we want a remainder of 4.... so what do you think we need to do?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
we need to stick something in that box so that our remainder is 4....
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
ok... how 'bout this....
 one year ago

sara1234Best ResponseYou've already chosen the best response.1
yeah what goes in the box?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
ok... sorry.. i made some typos up there... but this should be more clear...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
see the question mark? what should it be in order for our remainder to be 4?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
yes... i'm sorry i shuda done this way first.....
 one year ago

sara1234Best ResponseYou've already chosen the best response.1
okay gottcha thats the equation thats is a third degree polynomial that when divided by x + 2 has a remainder of –4. :)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
yes...:) again.... sorry....
 one year ago

dpaIncBest ResponseYou've already chosen the best response.5
thanks for sticking with me....:)
 one year ago
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