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alfers101
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Please help: Calculate the electric field at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge and the other three occupied by 27uC charges.
 2 years ago
 2 years ago
alfers101 Group Title
Please help: Calculate the electric field at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge and the other three occupied by 27uC charges.
 2 years ago
 2 years ago

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baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
sounds like physics bud
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
but i will help you anyway. you just need to find the NET electric field.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
if you want me to help. . .
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
Do you know the formula for electric field?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
is it E=F(R)/Q ??
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
\[E= kq/r^2\]
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay. then?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1340433733455:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
does the question say the side length of the square is 52.5cm?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
The question say: "at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge..."
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
okay, i'm going to assume the "side length" is 52.5cm
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay. i think it is the length.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1340433904871:dw
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
hmm i think thats it.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
you need the length from the corner to the charges. do you know how to find that?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
sorry i dont know.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
okay, if we have the side length of 52.5cm, to find the diagonal length we multiply this by \[\sqrt{2}\]
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
can you do that?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
52.5 * sqrt of 2 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
yes = ?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
but why sqrt of 2 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
because a square is in the form of x^2+y^2=2.. you can look into it later, and just trust me.
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay sure.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
haha, k... so that 74.25cm is the diagonal length, we divide this by 2 to give us the corner to center length
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
its 37.12
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
okay so now we can use our formula.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
E=(kq)/r^2
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
our k is 9x10^9 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
close enough, in physics we typically use 8.99 x 10^9
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
oh but can we use 9x10^9 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
we have to calculate each individual electric field. sure, it is close enough.
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay. then our Q is what? our R is 37.12 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
our q is the charge, there are 4 different charges. +45uC and 27uC, 27uC, 27uC
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
so we will use the four different charges? one by one?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
we will do two separate computations as three of them will be the same (27uC)
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
so lets get started
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay sure lets get started
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
fill this in with what we know: E=(kq)/r^2
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
or just do it on you're calculator and tell me the two answers
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
E=(9x10^9) (+45uC)/37.12 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
close... E=(9x10^9*45E6)/(37.12)^2 dont forget to square the denominator
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
and also remember the units for the charge is in micro coulombs
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
therefore 45E6
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
why is the exponent is 6 ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
i just told you, because the units are in uC
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
that little "u" mean E6
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
okay, so what your answer?
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
then the C means coulombs?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
correct
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
you used this? E=(9x10^9*45E6)/(37.12)^2
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
yup i did
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
well i'm afraid that is wrong, you must have typed it in wrong
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
http://www.wolframalpha.com/input/?i=%28%289x10%5E9%29%2845E6%29%29%2F%2837.12%29%5E2
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
let me check
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
E means exponent right?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
k dude, you take way to long. I need to sleep. You should get a value of 293.55 N/C for the +45uC and you should get 176.13 N/C for the 26uC
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
its 27uC
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
right, 27uC still the same answer.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
i think you should be able to do it from here.. i've been helping you for over an hour.
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
okay thank you so much.
 2 years ago
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