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anonymous
 3 years ago
Please help: Calculate the electric field at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge and the other three occupied by 27uC charges.
anonymous
 3 years ago
Please help: Calculate the electric field at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge and the other three occupied by 27uC charges.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sounds like physics bud

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i will help you anyway. you just need to find the NET electric field.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you want me to help. . .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know the formula for electric field?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340433733455:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does the question say the side length of the square is 52.5cm?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The question say: "at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge..."

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, i'm going to assume the "side length" is 52.5cm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay. i think it is the length.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1340433904871:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm i think thats it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you need the length from the corner to the charges. do you know how to find that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, if we have the side length of 52.5cm, to find the diagonal length we multiply this by \[\sqrt{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because a square is in the form of x^2+y^2=2.. you can look into it later, and just trust me.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha, k... so that 74.25cm is the diagonal length, we divide this by 2 to give us the corner to center length

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so now we can use our formula.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0close enough, in physics we typically use 8.99 x 10^9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh but can we use 9x10^9 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we have to calculate each individual electric field. sure, it is close enough.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay. then our Q is what? our R is 37.12 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0our q is the charge, there are 4 different charges. +45uC and 27uC, 27uC, 27uC

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we will use the four different charges? one by one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we will do two separate computations as three of them will be the same (27uC)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay sure lets get started

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0fill this in with what we know: E=(kq)/r^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or just do it on you're calculator and tell me the two answers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0E=(9x10^9) (+45uC)/37.12 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0close... E=(9x10^9*45E6)/(37.12)^2 dont forget to square the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and also remember the units for the charge is in micro coulombs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is the exponent is 6 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i just told you, because the units are in uC

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that little "u" mean E6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, so what your answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then the C means coulombs?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you used this? E=(9x10^9*45E6)/(37.12)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i'm afraid that is wrong, you must have typed it in wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=%28%289x10%5E9%29%2845E6%29%29%2F%2837.12%29%5E2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0E means exponent right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k dude, you take way to long. I need to sleep. You should get a value of 293.55 N/C for the +45uC and you should get 176.13 N/C for the 26uC

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right, 27uC still the same answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think you should be able to do it from here.. i've been helping you for over an hour.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay thank you so much.
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